Could you help me with the simplification of these kind of results?
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Really, I don't understand why Matlab is so horrible at making a decent simplification of fractions:
Look at this:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/323629/image.png)
For example, the first result is just this:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/323632/image.png)
How can I get a better simplification of these kind of results? I've tried simplify + other commands but just can't, it doesn't work
1 comentario
John D'Errico
el 29 de Jun. de 2020
Editada: John D'Errico
el 29 de Jun. de 2020
How many times will you ask the same question? How is this question fundamentally different from the last time you asked it?
That you think 1/sqrt(2) is simpler than sqrt(2)/2, is just your personal preference, a choice made by you, but apparently not preferred by symengine.
1/sqrt(sym(2))
ans =
2^(1/2)/2
I expect we will hear again, asking about a truly novel problem, like 1/sqrt(3).
Thankfully, you may give up by the time we get to 4.
1/sqrt(sym(4))
ans =
1/2
Respuestas (1)
Walter Roberson
el 29 de Jun. de 2020
Did you simplify() telling it to ignore analytic constraints?
If p0 is 0 then the expression to the power 0 would be 0^0 which is undefined. If you put in a constraint that forces p0 to be nonzero and m to be finite then the power 0 could be simplified.
1 comentario
Walter Roberson
el 29 de Jun. de 2020
Ah, is that a list of three different values, or is it a single expression that continues over multiple lines with the second term of the subtraction being raised to power 0?
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