# Add cut line (horizontal line) in bar graph

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Dionisio Mendoza el 30 de Jun. de 2020
Comentada: Image Analyst el 20 de Sept. de 2022
Hello everybody.
I just made a bar graph using the bar function, but I want a horizontal line to appear on the x axis. I know the xline function exists, but my MATLAB version appears to be old. Below I show the simple code.
x = [3.10,8.17,9.84,4.71,1.43,6.90,3.70,10.24,9.61,5.92,4.51,7.12,2.99,4.73,5.96,9.58,7.22,4.91,4.80,8.79,8.45,6.38,2.83,1.10,7.47,5.36,10.42,5.11,5.15,4.25,7.65,7.05,3.60,4.08,7.29,4.72,4.90,8.74,5.42,9.96,4.88,4.06,4.68,6.67,4.16,6.20,7.34,2.96,7.16,6.34,9.20,4.66,7.42,3.32,8.45,5.59,4.97,5.50,6.20,1.30,3.84,3.97,7.98,6.71,5.26,6.39,6.24,9.19,9.27,4.63,7.20,7.45,4.94,7.57,6.79,8.58,6.51,5.98,5.44,5.47,6.67,5.33,7.59,5.82,4.24,2.86,3.14,4.93,4.15,4.58,7.20,5.33,4.17,6.30];
bar(x,0.8,'w');
ylabel('volume')
xlabel('Pacients')
xticks([1:94]);
yticks([1:11]);
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Image Analyst el 30 de Jun. de 2020
Editada: Image Analyst el 30 de Jun. de 2020
Horizontal line on the x axis. What does that mean? The x axis is already horizontal so the line would overlap it. Do you mean horizontal line parallel with the x axis, intersecting the y axis at some value? xline() gives a vertical line, not a horizontal line. So we're not sure what you want. So I'm doing it both ways:
x = [3.10,8.17,9.84,4.71,1.43,6.90,3.70,10.24,9.61,5.92,4.51,7.12,2.99,4.73,5.96,9.58,7.22,4.91,4.80,8.79,8.45,6.38,2.83,1.10,7.47,5.36,10.42,5.11,5.15,4.25,7.65,7.05,3.60,4.08,7.29,4.72,4.90,8.74,5.42,9.96,4.88,4.06,4.68,6.67,4.16,6.20,7.34,2.96,7.16,6.34,9.20,4.66,7.42,3.32,8.45,5.59,4.97,5.50,6.20,1.30,3.84,3.97,7.98,6.71,5.26,6.39,6.24,9.19,9.27,4.63,7.20,7.45,4.94,7.57,6.79,8.58,6.51,5.98,5.44,5.47,6.67,5.33,7.59,5.82,4.24,2.86,3.14,4.93,4.15,4.58,7.20,5.33,4.17,6.30];
bar(x,0.8,'w');
ylabel('volume')
xlabel('Pacients')
xticks([1 : 10 : 94]);
yticks([1 : 11]);
grid on;
% Draw a vertical line at x = 50;
line([50, 50], ylim, 'Color', 'm', 'LineWidth', 2);
% Draw a horizontal line at y = 6;
line(xlim, [6, 6], 'Color', 'r', 'LineWidth', 2);
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Lavanya el 20 de Sept. de 2022
Ok, I will try to explain in a better way. As shown in 'image1.jpg', by using the ginput() , able to select the coordinates and using xline it's appearing as blue line. My question is If I want to try the ginput values manually( By using Editfield) the coordinates from the graph. Is it possible to that?
For example:
If I will give x=0.001,y = 12, from the edit field, 'image1.jpg', 1st blue line should appear.
Image Analyst el 20 de Sept. de 2022
Yes, does it not do that? Where did it draw the line when you ran my code. Perhaps start your own discussion thread.

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### Más respuestas (1)

Duijnhouwer el 30 de Jun. de 2020
Editada: Duijnhouwer el 30 de Jun. de 2020
hold on
plot(xlim,[5 5],'r-','LineWidth',2)
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Dionisio Mendoza el 1 de Jul. de 2020
Thanks for the help :).

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