# How do I define a structure that has an element which is an array?

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Wayne Prather on 6 Dec 2012
How do I define a structure that has an element which is an array and for which there are sub elements. I have composed a simple example below of what I want to do along with a failed attempt at the needed assert statements.
function y = payroll(personnel)
%#codegen
% Specify the class of the input as struct.
assert(isstruct(personnel));
% Specify the class and size of the fields r and i
% in the order in which you defined them.
assert(isa(personnel.num_employees,'int32'));
assert(isa(personnel.employee,'int32'));
assert(all(size(personnel.employee) == [5 1]));
assert(isa(personnel.employee(1).salary,'int32'));
for i = personnel.num_employees
total_payroll = total_payroll + personnel.name(i).salary;
end
y = total_payroll;
end
Sean de Wolski on 7 Dec 2012

Fred Smith on 7 Dec 2012
This line seems wrong:
assert(isa(personnel.employee,'int32'));
In your code employee is supposed to be a struct with sub-field name and salary? Once you make it a struct, you then also need to set its class and size of the fields name and salary.
-Fred
Wayne Prather on 7 Dec 2012
It finally works. Apparently you have to define the arrayed sub elements in the same way that you define the main structure. The following Matlab code works and succesfully produces the C++ code that follows.
Matlab code:
function y = payroll(personnel)
%#codegen
% Specify the class of the input as struct.
assert(isstruct(personnel));
% Specify the class and size of the fields r and i
% in the order in which you defined them.
assert(isa(personnel.num_employees,'int32'));
assert(isstruct(personnel.employee));
assert(all(size(personnel.employee) == [5 1]));
assert(isa(personnel.employee(1).salary,'double'));
total_payroll = 0;
for i = 1 : personnel.num_employees
total_payroll = total_payroll + personnel.employee(i).salary;
end
y = total_payroll;
end
Matlab Coder produced C++ code:
real_T payroll(const b_struct_T personnel)
{
real_T y;
int32_T i;
y = 0.0;
for (i = 1; i <= personnel.num_employees; i++) {
y += personnel.employee[i - 1].salary;
}
return y;
}

John Petersen on 6 Dec 2012
Edited: John Petersen on 6 Dec 2012
1. Find out which assertion fails. The code looks fine.
2. Replace the 'for' loop with
y = sum([personnel.name.salary]);

Jan on 7 Dec 2012
This will crash, if the personnel.employee has more than 2 dimensions:
all(size(personnel.employee) == [5 1])
Better:
isequal(size(personnel.employee), [5 1])

Sean de Wolski on 7 Dec 2012
total_payroll = total_payroll + personnel.name(i).salary;
total_payroll is never defined before being used for the first time!
Wayne Prather on 7 Dec 2012
Thanks, you are correct. I forgot to initialize it. The code is just a made up simplistic example that addresses the problem I am having in my real code in regards to defining a structure with elements which are arrays for the C++ code generation.

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