Quotes around the name of the function
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When do we put quotes around the name of the function and when not ? For example, I used fsolve(myfun,x0) and I got no results , but when I used fsolve('myfun',x0) I got the root I was looking for ...
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Matt Fig
el 15 de Dic. de 2012
Editada: Matt Fig
el 15 de Dic. de 2012
Typically, you want to pass a handle to a function, not a string.
fsovle(@myfun,x0) % Notice the @ symbol --> a function handle.
The string argument gets evaluated the same way, probably for backward compatibility. The modern way is to use function handles.
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Matt Fig
el 15 de Dic. de 2012
You would have to show exactly what you did in order for me to know why one code failed.
f = @(x) exp(x) - cos(x) - 1; % f is a function handle.
fsolve(f,0) % Seems to work....
f = @(x) exp(x) - x^2 - 68 ; % Another function handle.
fsolve(f,0) % Also works....
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