Index in position 2 exceeds array bounds (must not exceed 2).

I am trying to write code to delete every column of a matrix that has 0 in the second row so I am only left with the columns that have values in that second row. The code works okay and does that but I keep getting the error "Index in position 2 exceeds array bounds (must not exceed 2)."

I need to use the values after and I keep running into the same problem. Can I get some help?

This is what my code looks like :

c= length(fill); 
while c >= 1
    if fill(2,c) == 0;
    fill(:,c) = [];
    c = length(fill);
    else
    c = c - 1;
    end
end

fill is typically a 3 by 30 ish matrix (it changes for each set of data).

Answer 1

[madhan ravi]

Never name a variable fill !

 ix = FiLL(2, :) == 0;
 FiLL(:, ix) = []

[Anjolaoluwa Bamtefa]

Thank you very much! fill was a temporary name but I see now that it is a keyword.

Answer 2

[Bhupendra Prajapati]

length function will give maximum of rows or columns in the matrix, you should use size function to calculate number of columns

You can use the code given below to do your task.

[r,c]=size(fill)
id=1;
while(id<=c)
    if(any(fill(2,id)==0))
        fill(:,id)=[];
        c=c-1;
    else
        id=id+1;
    end
end

[madhan ravi]

As mentioned above , not a good idea to use fill as a variable name. And loop is totally unnecessary here.