How to parse a Matrix ODE45. Getting simulation error

Hi Dears!
I am simulating a set of Ordinary Differntial Equations ODEs using ODE45 solver. I need to parse a matrix (i.e. zeta=rand(46,16)) into the ODE45, however I am getting this error:
Unable to perform assignment because the left and right sides have a different number of elements.
Error in OscillatorExample_V2>LinearOscillatorFree (line 26)
y(2)=(-2*zeta*y(2))-(w*y(1));
Error in odearguments (line 90)
f0 = feval(ode,t0,y0,args{:}); % ODE15I sets args{1} to yp0.
Error in ode45 (line 115)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in OscillatorExample_V2 (line 9)
[T, Y] = ode45(@LinearOscillatorFree, tspan, initcond, [],zeta);
Can you please help me with this to get the right results? Many thanks in advance!
close all; clear all; clc;
zeta=rand(46,16);
tspan=[0 4700];
initcond= [0 1];
for n = 1:length(zeta)
[T, Y] = ode45(@LinearOscillatorFree, tspan, initcond, [],zeta);
figure(1);
plot(T, Y(:,1));
hold on
end
m= length(Y);
for i=1:m
y(i,:)=feval('LinearOscillatorFree',T(i),Y(i,:),zeta);
end
y=y';
function dy = LinearOscillatorFree(t, y,zeta)
w=0.5;
y(1)=y(2);
y(2)=(-2*zeta*y(2))-(w*y(1));
dy= [y(1); y(2)];
end

7 comentarios

What is the ODE you are trying to solve, and what is the purpose of zeta?
Shy
Shy el 27 de Jul. de 2020
The used ODE is ode45, and the purpose of zeta is a matrix which is parsed into the (LinearOscillatorFree) function I used in my code.
I mean, what is the differential equation you are trying to solve? Post the equation for us to see, with a definition of zeta. Are you trying to run a Monte-Carlo simulation with various random values of zeta?
Shy
Shy el 27 de Jul. de 2020
Hi James,
This is my code with the definition of zeta and the differential equations: (Yes I am using a Monte-Carlo simulation)
close all; clear all; clc;
zeta=rand(46,16);
tspan=[0 4700];
initcond= [0 1];
for n = 1:length(zeta)
[T, Y] = ode45(@LinearOscillatorFree, tspan, initcond, [],zeta);
figure(1);
plot(T, Y(:,1));
hold on
end
m= length(Y);
for i=1:m
y(i,:)=feval('LinearOscillatorFree',T(i),Y(i,:),zeta);
end
y=y';
function dy = LinearOscillatorFree(t, y,zeta)
w=0.5;
y(1)=y(2);
y(2)=(-2*zeta*y(2))-(w*y(1));
dy= [y(1); y(2)];
end
Shy
Shy el 27 de Jul. de 2020
Editada: Shy el 27 de Jul. de 2020
These are the differential equations:
James Tursa
James Tursa el 27 de Jul. de 2020
Editada: James Tursa el 27 de Jul. de 2020
Your equations don't make sense to me. How can y1 and y2 be scalars and yet zeta be a matrix? The dimensions of the equations don't match. It might make sense for zeta fo be a scalar that is randomly selected from a distribution, and then run Monte-Carlo on that. But what you have written doesn't make sense. Where did these equations come from? Why the 46x16 size of zeta?
Shy
Shy el 27 de Jul. de 2020
I am running a similar system like that consisting of four ODEs, so the question is how to parse a matrix into the ode45 solver? Can you please provide me with your email so that I can email you on?

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Shy
el 27 de Jul. de 2020

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Shy
el 27 de Jul. de 2020

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