# finding minimum value in Quanterion matrix

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FIR el 21 de Dic. de 2012
I have a 386x514 quaternion array,in this please tell how to find the minimum value of that matrix
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FIR el 21 de Dic. de 2012
My form is 384x512 pure quaternion array with uint8 components
if i use min i get error
Undefined function or method 'min' for input arguments of type 'quaternion'.
Matt J el 21 de Dic. de 2012
FIR Commented:
FIR Commented:
Sorry Matt my code [which doesn't work] is
T=65;
for i=2:6
for j=2:6
q= A(i-1:i+1,j-1:j+1);
[minsum, minidx] = min( sum(abs(bsxfun(@minus, q(:), q(:).'))) );
qVFM = q(minidx);
V1=an equation
V2=an equation
S=min([V1 V1]);
if S>T
THE CENTRE PIXEL IS REPLACED BY qVFM %%%%3x3 matrix
else
THE CENTRE PIXEL IS not REPLACED BY qVFM%%%%3x3 matrix
end
end
end

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Matt J el 21 de Dic. de 2012
Editada: Matt J el 21 de Dic. de 2012
BSXFUN isn't overloaded well in the quaternion toolbox that you're using. Here is a workaround
q= convert(A(i-1:i+1,j-1:j+1),'single');
[minsum, minidx] = min( sum(abs( repmat(q(:),1,9)-repmat(q(:).',9,1) ) ));
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Matt J el 22 de Dic. de 2012
Isn't the center pixel A(i,j)? If so, do A(i,j)=whatever.
Walter Roberson el 22 de Dic. de 2012
Or, since that would affect the computations as you slid the window, create a second array and set the pixels in it -- as I showed you in one of your previous questions.

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