# finding minimum value in Quanterion matrix

2 views (last 30 days)
FIR on 21 Dec 2012
I have a 386x514 quaternion array,in this please tell how to find the minimum value of that matrix
Matt J on 21 Dec 2012
FIR Commented:
FIR Commented:
Sorry Matt my code [which doesn't work] is
T=65;
for i=2:6
for j=2:6
q= A(i-1:i+1,j-1:j+1);
[minsum, minidx] = min( sum(abs(bsxfun(@minus, q(:), q(:).'))) );
qVFM = q(minidx);
V1=an equation
V2=an equation
S=min([V1 V1]);
if S>T
THE CENTRE PIXEL IS REPLACED BY qVFM %%%%3x3 matrix
else
THE CENTRE PIXEL IS not REPLACED BY qVFM%%%%3x3 matrix
end
end
end

Matt J on 21 Dec 2012
Edited: Matt J on 21 Dec 2012
BSXFUN isn't overloaded well in the quaternion toolbox that you're using. Here is a workaround
q= convert(A(i-1:i+1,j-1:j+1),'single');
[minsum, minidx] = min( sum(abs( repmat(q(:),1,9)-repmat(q(:).',9,1) ) ));
Walter Roberson on 22 Dec 2012
Or, since that would affect the computations as you slid the window, create a second array and set the pixels in it -- as I showed you in one of your previous questions.