# Sort rows of a table by column within a variable

1 view (last 30 days)
J AI on 28 Jul 2020
I have a table:
T =
a v
________ _______________________________
0.88517 0.33536 0.65376 0.89092
0.91329 0.67973 0.49417 0.33416
0.79618 0.13655 0.77905 0.69875
0.098712 0.72123 0.71504 0.19781
0.26187 0.10676 0.90372 0.030541
I want to sort the table using the last column of v. This is the closest I could find but obviously it does not work (thus I am posting the question):
sortedT = sortrows(T,'v')
I am not sure how it sorts in this case:
sortedT =
a v
________ _______________________________
0.26187 0.10676 0.90372 0.030541
0.79618 0.13655 0.77905 0.69875
0.88517 0.33536 0.65376 0.89092
0.91329 0.67973 0.49417 0.33416
0.098712 0.72123 0.71504 0.19781
I also looked up in sortrow documentation but could not find anything there (did I slip?).
Your help is highly appreciated! Thank you.

Behzad Navidi on 28 Jul 2020
I think it could be done if you convert your table to matrix then sort it as you like and the return it to table. Jus an idea...
J AI on 28 Jul 2020
Yes, I suppose I could do that. I have actually achieved what I was trying to achieve in a different way already. So, just as a learning process, let's see if there is a direct way we can achieve this.

Harsha Priya Daggubati on 30 Jul 2020
Hi,
As you can see from the data, whenever you apply sortrows to your table, by giving your column name as 'v' data will be sorted based on the first column of your merged column 'v'.
As a workaround, you can use 'splitvars' method to update your table and apply sortrows, then later merge your table which you need as a final result using 'mergevars'.
Here is the code to it:
a = [0.88517 ;0.91329;0.79618;0.098712;0.26187];
v = [ 0.33536 0.65376 0.89092; 0.67973 0.49417 0.33416; 0.13655 0.77905 0.69875; 0.72123 0.71504 0.19781; 0.10676 0.90372 0.030541];
tbl = table(a,v)
tbl1 = splitvars(tbl);
tbl1 = sortrows(tbl1,[4]);
finaltbl = mergevars(tbl1,[2 3 4],'NewVariableName','v');
Hope this helps!

R2020a

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by