How to loop through the table and assign 1's with an if statement

I want to loop through dataFix (which is 8 columns wide and 39500 rows).

If there is a 1 in that cell in dataFix, and ALSO a 1 in the corresponding row of Speaking (which is a 1 column wide and 39500 rows long), I want dataSpeak to be a 1, if not 0.

dataSpeak is the same dimensions as dataFix.

At the moment, dataSpeak is just zero's and the 1's are not being correctly assigned.

Thank you!

dataSpeak=zeros(maxTime,nUP)

for l=1:length(dataFix)

if dataFix==1 & Speaking ==1;

dataSpeak=1;

end

end

Answer 1

[Cristian Garcia Milan]

Can you use?

dataSpeak=zeros(maxTime,nUP)
for l=1:length(dataFix) 
if dataFix(i)==1 & Speaking(i) ==1;
 dataSpeak(i)=1; 
 end
end

dataSpeak variable needs another index due to it has 2 dimensions.

[Jessica Dawson]

Hi, thank you for your answer!

(I changed your i's to l's? as I think that is what you meant as i is not defined anywhere?)

This seems to do the trick for the first column of dataSpeak only! So it needs to do the same for the other 7 columns.

Thank you!

[Cristian Garcia Milan]

Sorry for the i index, I used it because it is the typical I use haha.

If you want to go down the other 7 colums, you have to use another for-loop:

dataSpeak=zeros(maxTime,nUP);
for l=1:size(dataFix,1)
    for m=1:size(dataFix,1)
        if dataFix(l,m)==1 & Speaking(l,m) ==1;
            dataSpeak(l)=1; 
        end
    end
end

But one for-loop inside another one is quite-slow, so I suggest you to use:

dataSpeak=zeros(maxTime,nUP);
idx = dataFix==1 & Speaking ==1;
dataSpeak(idx) = 1;

[Jessica Dawson]

This looks great and this is much simpler! Thank you so much!