How to calculate max multiplication possibility of three adjacent numbers in 10*10 matrix?
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Asrorkhuja Ortikov
el 17 de Ag. de 2020
Comentada: Asrorkhuja Ortikov
el 17 de Ag. de 2020
I have a matrix of 10 to 10 size of random digits from 0 to 9. How to calculate possible max multiplication of three adjacent numbers in matrix? I would like to consider only vertical and horizontal adjacent numbers, not diagonal.
r = randi([0 9],10,10);
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Bruno Luong
el 17 de Ag. de 2020
% Test matrix
A=randi([0 9],10,10)
B=cat(3,movprod(A,3,1),movprod(A,3,2));
[maxB,imax]=max(B,[],'all','linear');
[i,j,k]=ind2sub(size(B),imax);
if k==1
i=max(i-1,1):min(i+1,size(A,1));
j=j+zeros(size(i));
else
j=max(j-1,1):min(j+1,size(A,2));
i=i+zeros(size(j));
end
ilin = sub2ind(size(B),i,j);
% Display the adjadcent elements
fm1 = repmat('A(%d,%d)*', 1, length(i));
fm1(end) = [];
fm2 = repmat('%d*', 1, length(i));
fm2(end) = [];
fprintf(['%d = ' fm1 ' = ' fm2, '\n'], maxB, [i(:) j(:)]', A(ilin));
3 comentarios
Bruno Luong
el 17 de Ag. de 2020
The size of the array is in the first line
A=randi([0 9],10,10)
The length of the adjacent elements are in the second arguments of MOVPROD in the second statement
B=cat(3,movprod(A,3,1),movprod(A,3,2));
Más respuestas (1)
Walter Roberson
el 17 de Ag. de 2020
conv2(A, ones(1,n), 'same')
and same with ones(n, 1)
take max() over all of it.
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