HI,
I've noticed this question appears a lot, and I watched the video here :https://www.mathworks.com/videos/storing-data-in-a-matrix-from-a-loop-97493.html, but I haven't been able to figure it out for my own code. The code outputs a value for the area, however doesn't store it as a variable. Any suggestions?
clc;
clear;
x = [ 0 1 2 3 4 5 6 7 8 9 10 11 12];
y = [0 -0.5 -0.8 -0.8 -1 -1.1 -1.2 -1.2 -1.4 -1.2 -1.1 -1 0];
for h0= -2:0.04:1;
h=ones(size(x))*h0;Int=pchip(x,y);xx=linspace(x(1),x(end),500);
yy=y-h0;yyy=pchip(x,yy,xx);gt=yyy<0;
Area =-trapz(xx(gt), (yyy(gt)))
hold off
area(xx, min(ppval(Int,xx), h(1)), h(1), 'EdgeColor', 'none', 'FaceColor', 'b'),grid,
end

 Respuesta aceptada

Alan Stevens
Alan Stevens el 23 de Ag. de 2020
Something like
...
k = 0;
for h0= -2:0.04:1;
k = k+1;
h=ones(size(x))*h0;Int=pchip(x,y);xx=linspace(x(1),x(end),500);
yy=y-h0;yyy=pchip(x,yy,xx);gt=yyy<0;
Area(k) =-trapz(xx(gt), (yyy(gt)));
...etc.

3 comentarios

Hamzah Mahmood
Hamzah Mahmood el 23 de Ag. de 2020
Thanks Alan, that makes a lot of sense now actually. Cheers.
Hamzah Mahmood
Hamzah Mahmood el 23 de Ag. de 2020
One more follow up question. Currently h0 is being stored as a single variable that is being overwritten, could I use a similar line of code to store that as the range I'm calculating for?
You could rearrange the coding as follows:
h0= -2:0.04:1;
for k= 1:length(h0);
h=ones(size(x))*h0(k);Int=pchip(x,y);xx=linspace(x(1),x(end),500);
yy=y-h0(k);yyy=pchip(x,yy,xx);gt=yyy<0;
Area(k) =-trapz(xx(gt), (yyy(gt)));
... etc.
(notice that h0 now becomes h0(k) within the loop) then all values of h0 are available after the loop ends.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

Preguntada:

el 23 de Ag. de 2020

Comentada:

el 23 de Ag. de 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by