ellipse fitting with matlab using fittype
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Johannes Tischer
el 25 de Ag. de 2020
Comentada: Matt J
el 27 de Ag. de 2020
Hello,
I want to use fitoptions and fittype for a staistical nonlinear least squares fitting approach. The problem is, I cant find the correct equation for my model (ellipse). I tried multiple like: to fittype ('sqrt(b^2*(1-(x^2/a^2)))' ). In this example, the square root has to be positive. I tried to tightening the upper and lower bounderies, but it doesnt work.
Can someone make an example of the following form:
fo = fitoptions('Method','NonLinearLeastSquares')
ft = fittype('ellipse equation')
[myfit, gof] = fit(x_data, y_data, ft, fo)
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Matt J
el 26 de Ag. de 2020
Editada: Matt J
el 26 de Ag. de 2020
You could use fit() if you convert your data to polar cooridnates. In polar coordinates, an ellipse is given by an explicit function,
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Matt J
el 27 de Ag. de 2020
The problem with this method, of course, is that it assumes that the ellipse is centered at the origin. In general, that may not be true or known to be true.
Más respuestas (3)
Alan Stevens
el 25 de Ag. de 2020
Have a look here: https://uk.mathworks.com/help/curvefit/fittype.html?s_tid=srchtitle
It shows you how to construct your own function correctly.
6 comentarios
Alan Stevens
el 26 de Ag. de 2020
Hmm. I'm struggling to see your basic data as elliptical. Nevertheless, the code below tries to fit them using an ellipse (I've deleted a few obvious non-elliptical outliers below; however, you could easily retain them if you wish):
load('EllipseData.mat')
% The next three lines remove outliers that are obviously not part of an
% ellipse! Delete the three lines if you wish to retain the outliers.
ix = find(data_x<-600); data_x(ix) = [];data_y(ix) = [];
iylo = find(data_y<-220); data_x(iylo) = [];data_y(iylo) = [];
iyhi = find(data_y>220); data_x(iyhi) = [];data_y(iyhi) = [];
% Set the origin at the means of the x and y data
x = data_x - mean(data_x);
y = data_y - mean(data_y);
% "Linearise" and do a straightforward least-squares fit
N = length(x);
X = x.^2; Y = y.^2;
M = [N -sum(X); sum(X) -sum(X.^2)];
V = [sum(Y); sum(X.*Y)];
AB = M\V; % AB = [A; B]
% Extract constants
A = AB(1);
B = AB(2);
% Create ellipse semimajor axes from "linear" constants
a = sqrt(A/B);
b = sqrt(A);
% Separate upper and lower halves of "elliptical" values.
xhi = x(x>=0); xlo = x(x<0);
yhi = b*sqrt(1 - (xhi/a).^2);
ylo = -b*sqrt(1 - (xlo/a).^2);
% Put them back together and shift the origin back
xf = [xhi xlo] + mean(data_x);
yf = [yhi ylo] + mean(data_y);
% Plot and compare Data and fit.
plot(data_x,data_y,'o',x,yf,'*'), grid
xlabel('x'),ylabel('y')
legend('Data','"Elliptical" fit')
This is the result:
Image Analyst
el 26 de Ag. de 2020
For what it's worth, attached is a paper that describes the method.
Least Squares orthogonal distances fitting of circle, sphere, ellipse, hyperbola, and parabola.pdf
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