Split cell arrays into seperate matrix; Indexing problem with cell array

Hello guys, thank you very much in advance. I woul like to split up a cell array (NxM) with (1xR) double elements in each cell into m matrix or tables with (NxM).

For your further information about my situation: I have different simulation settings (NxM) and i have different result outputs which are the data in each cell (1xR).

My goal is to get a matrix or table for each result. That means I want R matrix with (NxM) Data of the fitting result

Maybe you could help me with a neat solution

a={[1,2],[1,2],[1,2];[1,2],[1,2],[1,2];[1,2],[1,2],[1,2]} %easy number exmaple
%%%%%%%%%%
Result1=[1,1,1;1,1,1;1,1,1]%Result matrix 1; Result1 through indexing of a
Result2=[2,2,2;2,2,2;2,2,2]%Result matrix 2;Result2 through indexing of a

This is probably trivial but I am not able to make it work without using a for-loop. And everytime I use a for-loop i get stuck with the variable naming of the result matrix.

Thank you very much!

[Stephen23]

"And everytime I use a for-loop i get stuck with the variable naming of the result matrix."

Why do you want to force yourself into writing slow, complex, obfuscated, buggy code that is hard to debug?

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Indexing is much neater, simpler, more efficient, less buggy, and easier to debug.

Answer 1

[Stephen23]

"Maybe you could help me with a neat solution"

The neat solution is to use MATLAB's arrays effectively. For example, something like this:

>> a = {[1,2],[1,2],[1,2];[1,2],[1,2],[1,2];[1,2],[1,2],[1,2]};
>> s = size(a);
>> m = reshape(vertcat(a{:}),s(1),s(2),[]);
>> m(:,:,1) % index 1st page
ans =
   1   1   1
   1   1   1
   1   1   1
>> m(:,:,2) % index 2nd page
ans =
   2   2   2
   2   2   2
   2   2   2

https://www.mathworks.com/help/matlab/math/multidimensional-arrays.html

Using different values makes the example clearer:

>> a = {[1,2],[3,4],[5,6];[7,8],[9,10],[11,12];[13,14],[15,16],[17,18]};
>> s = size(a);
>> m = reshape(vertcat(a{:}),s(1),s(2),[]);
>> m(:,:,1) % index 1st page
ans =
    1    3    5
    7    9   11
   13   15   17
>> m(:,:,2) % index 2nd page
ans =
    2    4    6
    8   10   12
   14   16   18
>> c = num2cell(m,1:2); % optional: a cell array may be convenient in some situations.
>> c{1} % index 1st cell
ans =
    1    3    5
    7    9   11
   13   15   17
>> c{2} % index 2nd cell
ans =
    2    4    6
    8   10   12
   14   16   18

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

[Siegfried Suthau]

Stephen, I do completely agree with you! I do not want to use for loops. But as a beginner I want to check everything in my mind for a possible solution before asking someone else!

Is there a specific reason you want to change c with num2cell? Not using num2cell, i can get the data via c(:,:,1) or c(:,:,1) . I was working through your c= command and was wondering why you want to use num2cell

Thanks again Stephen!:)

[Stephen23]

@Siegfried Suthau : num2cell is completely optional. I have altered my answer slightly to make this clear.