Borrar filtros
Borrar filtros

Finding the definite integral of a constant?

2 visualizaciones (últimos 30 días)
Rachel
Rachel el 16 de En. de 2013
Hello. I'm writing a program for class which solves Gauss's Law numerically and plots points. The problem I'm running into is in the integral. Gauss's Law for a sphere can be rearranged into two definite integrals: the integral of sin(theta) from 0 to pi and the integral of 1 from 0 to 2pi. I used trapz for both:
theta = 0:pi/100:pi;
polarintegral = sin(theta);
phi = 0:pi/100:2*pi;
azimuthintegral = 1;
polar = trapz(theta, polarintegral);
azimuth = trapz(phi, azimuthintegral);
The theta integral works perfectly. Matlab, however, doesn't seem to understand how to integrate 1, since it's not a function of phi. The project instructions says that we're not allowed to solve the integral for the program, even if it's simple. Does anybody have any ideas how I might be able to fix this snag?
By the way, I'm using Matlab 2009b in case that makes a difference. Thank you!

Respuesta aceptada

Shashank Prasanna
Shashank Prasanna el 16 de En. de 2013
Editada: Shashank Prasanna el 16 de En. de 2013
Maybe you want to do this instead:
az = ones(length(phi),1);
azimuth = trapz(phi, az)
  1 comentario
Rachel
Rachel el 16 de En. de 2013
Thank you so much! It worked perfectly and now my program runs like it should! Now to adapt it for the more complex problems.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Programming en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by