recursive function to calculate Max number.
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    Urmish Haribhakti
 el 9 de Sept. de 2020
  
    
    
    
    
    Respondida: Welid Benchouche
 el 18 de Ag. de 2021
            function mx=recursive_max(v)
if numel(v)==1
    mx=v;
end
if numel(v)>1
    mx= recursive_max(1);
end
this much i've got so far.
Please help with this code.
1 comentario
  JAYANTHI SANKARALINGAM
 el 20 de Sept. de 2020
				When we use this,it shows error as
incorrectRandom vector Variable mx has an incorrect value. Test failed using v =[ 14 92 89 27 8 ]
Respuesta aceptada
  Stephen23
      
      
 el 10 de Sept. de 2020
        
      Editada: Stephen23
      
      
 el 10 de Sept. de 2020
  
      Urmish Haribhakti's general approach is quite good, with a few small changes it will work correctly:
function x = recmax(v)
if numel(v)<=1
    x = v;
else
    x = recmax(v(2:end));
    if v(1)>x
        x = v(1);
    end
end
end
And tested:
>> recmax([28,2,6,1,999,8])
ans =  999
2 comentarios
Más respuestas (5)
  Mati Somp
      
 el 9 de Oct. de 2020
        One more 
function mx = recursive_max(v)
 if length(v)==1
     mx=v
 else
         if v(1)<=v(2)
                v(1)=[]
           else 
                v(2)=[]
           end
         mx=recursive_max(v)
  end
1 comentario
  xin yi leow
      
 el 25 de En. de 2021
				This works for me and is easy to understand! if v(1) < v(2), we remove the first element, and if v(2)<v(1), we remove the v(2), that way we only keep the larger of the 2 elements in the vector. The last remaining element will naturally be the largest one. 
  Ameer Hamza
      
      
 el 9 de Sept. de 2020
        
      Editada: Ameer Hamza
      
      
 el 10 de Sept. de 2020
  
      Something like this:
function mx = recursive_max(v)
    x = zeros(1, 2);
    if numel(v) > 2
        a = floor(numel(v)/2);
        x(1) = recursive_max(v(1:a));
        x(2) = recursive_max(v(a+1:end));
    elseif numel(v) == 1
        x = [v -inf];
    else
        x = v;
    end
    if x(1) > x(2)
        mx = x(1);
    else
        mx = x(2);
    end
end
I am not sure if this is an optimal algorithm.
2 comentarios
  Piyush Gupta
 el 10 de Sept. de 2020
				
      Editada: Piyush Gupta
 el 10 de Sept. de 2020
  
			can you explain the code....
  Ameer Hamza
      
      
 el 10 de Sept. de 2020
				It divides the input vector into two parts recursively. When the length of the divided vector reaches two during recursion, the recursion stops, and the function returns back the largest of the two elements.
  JAYANTHI SANKARALINGAM
 el 20 de Sept. de 2020
        Write a function called recursive_max that finds the maximum element in a vector without using loop or any built in functions.the sole output argument is the maximum value in the input vector.
1 comentario
  Himalsha Dharmapala
 el 15 de En. de 2021
        function output= recursive_max3(v)
 if v(1,:)==0
     output=v(1);
  else
     if v(end)>=v
         output=v(end);
     else 
         output= recursive_max3(v(1:end-1));
     end     
  end
end
0 comentarios
  Welid Benchouche
 el 18 de Ag. de 2021
        my solution to this assignment is 
function mx = my_recursive_max(v)
% base case
if length(v) == 1
    mx = v;
else
% recursive case
a = v(end);
b = v(1);
if a <= b
    mx = b;
    mx = my_recursive_max(v(1:end-1))
else
    mx = a;
    mx = my_recursive_max(v(2:end))
end
end
0 comentarios
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