How to use a for loop to solve a function?

Not sure where I'm going wrong. While loop works correctly, but not sure what's happening with the for loop.
x=linspace(0,20,20);
a=0;
while(a<=20)
y=x.^6-(3.*x).^2+3.^x-(230.*x);
a=a+1;
end
for j=1:20
y2(j)=100.*3log(j)-(2.*j);
end
When plotting, the while loop plots how it should, but nothing shows up for the for loop. Any guidance welcome. Thank you!

Respuestas (1)

Ameer Hamza
Ameer Hamza el 13 de Sept. de 2020
In your code, the while loop has no use. I think you wanted to write it like this
while(a<=20)
y(a)=x(a).^6-(3.*x(a)).^2+3.^x(a)-(230.*x(a));
a=a+1;
end
The for loop seems fine except there is a typing error. Following should work fine and you can plot the output
for j=1:20
y2(j)=100.*3*log(j)-(2.*j);
end

2 comentarios

Jer D
Jer D el 13 de Sept. de 2020
Sorry for the confusion. The while loop was used to solve for one function, and the for loop is for another function. I'm trying to get them to plot on one graph however, only the while loop is graphing which made me assume that my for loop isn't working. For some reason, the for loop won't graph at all.
Ameer Hamza
Ameer Hamza el 14 de Sept. de 2020
Editada: Ameer Hamza el 14 de Sept. de 2020
They are both visible, but y2 have very small values as compared to y, so it is on lower part axes (see the orange line on x-axes
x=linspace(0,20,20);
a=1;
while(a<=20)
y(a) = x(a).^6-(3.*x(a)).^2+3.^x(a)-(230.*x(a));
a=a+1;
end
for j=1:20
y2(j) = 100.*3*log(j)-(2.*j);
end
f = figure();
hold on;
plot(y);
plot(y2);

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el 13 de Sept. de 2020

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el 14 de Sept. de 2020

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