Legend and Colors for Iteration function
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A.J.M
el 14 de Sept. de 2020
Comentada: A.J.M
el 15 de Sept. de 2020
Good Day;
I need the steps that I can add Legend to my iteration function, where there are four curves, therefore, for each curve there must have specific color and legend that point to it.
Many Thanks
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Respuesta aceptada
Adam Danz
el 14 de Sept. de 2020
Editada: Adam Danz
el 14 de Sept. de 2020
Use the displayname property to assign the legend string and use the "color" property to set the line color.
% Define colors
n = 12;
colors = jet(n);
% Plot within loop
hold on % Important!
for i = 1:n
plot(1:5, rand(1,5), '-', 'Color', colors(i,:),...
'DisplayName', sprintf('Line #%d',i));
end
legend()
14 comentarios
Adam Danz
el 15 de Sept. de 2020
I see the problem. Look at the values you're plotting.
semilogy(z,PDF_Hp,'LineWidth',4);
PDF_Hp =
Columns 1 through 12
59.204 0 0 0 0 74.572 0 0 0 0 130.59 0
33.684 0 0 0 0 41.243 0 0 0 0 66.92 0
5.2821 0 0 0 0 5.3479 0 0 0 0 5.1881 0
0.42448 0 0 0 0 0.30818 0 0 0 0 0.12088 0
Columns 13 through 16
0 0 0 242.89
0 0 0 112.93
0 0 0 4.5326
0 0 0 0.032869
A line is created for each column so your plot actually has 16 lines, not 4.
The reason they don't appear is because in a log plot, 0 is not defined. However, those line objects are still produced - they are just not shown. As evidence of that, check out the 16 object handles.
h = semilogy(z,PDF_Hp,'LineWidth',4)
% h =
% 16×1 Line array:
%
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
% Line
The reason the "wrong" colors are defined is because you're only asking for the first 4 objects to appear in the legend. But objects 2-3-4 are all non-visible lines.
legend('σ^2_I=0.1','σ^2_I=0.2','σ^2_I=0.5','σ^2_I=0.8')
Solution
Get rid of the columns with 0s in PDF_Hp
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