Adding successive cells in a columns
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Isaac Ahenkorah
el 18 de Sept. de 2020
Respondida: Isaac Ahenkorah
el 18 de Sept. de 2020
Hi,
I have a table (1x7921). I want to add successive columns. For example add column 1:16, 17:32, 32: 48 etc.
Is there a code that I can used to successively add specific range of columns?
4 comentarios
Walter Roberson
el 18 de Sept. de 2020
Row 1 is not numeric. You then have 15 numeric rows after that that are to be added to give the yellow result. Then you add the next 16 entries to give the green result. Are you sure you want the yellow to have only 16 numeric entries added together? And as madhan points out, there would be one extra row left over, with a group ending at 7920 . Are you sure you want the last group to be only one number by itself?
It would make a lot more sense to discard that non-numeric first row and add groups of 16 after that.
Respuesta aceptada
Walter Roberson
el 18 de Sept. de 2020
sum(reshape(table2array(YourTable), 16, []))
but having a table object with only one row and 7921 variables is not at all common. It would be far more likely that you have a numeric vector, in which case
sum(reshape(YourVector, 16, []))
2 comentarios
Walter Roberson
el 18 de Sept. de 2020
Good point. But 7920 is divisible by 16, and the user shows a text entry in the first row, so it is plausibly 7920 rows of numeric values.
Más respuestas (2)
madhan ravi
el 18 de Sept. de 2020
Editada: madhan ravi
el 18 de Sept. de 2020
Assuming after sir Walter’s comment:
T = TabLe{:, :};
n = numel(TabLe);
t = [TabLe, nan(1, 16 - mod(n, 16))];
Wanted = sum(reshape(t, [], 16), 'omitnan') % nansum() for older versions
2 comentarios
madhan ravi
el 18 de Sept. de 2020
Both sir Walter’s answer and my answer should work , once you read the data using readtable()
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