For loop versus Matrix notation

1 visualización (últimos 30 días)
mutt
mutt el 29 de En. de 2013
Can this be simplified to use a matrix expression instead of a for loop?:
X=[1 5.4; 1 6.3; 2 4.8; 3 7.1];
dates=X(:,1);
amounts=X(:,2);
uniquedates=unique(dates);
totals=zeros(size(uniquedates));
for d = 1:size(uniquedates,1)
totals(d,1)=sum(amounts(dates==uniquedates(d,1)));
end
Y = [uniquedates totals];
  2 comentarios
Matt Kindig
Matt Kindig el 29 de En. de 2013
Probably, but likely not in an easy-to-understand way. The fact that totals differs in size from dates complicates things.
Is there a reason you don't want to just use the for-loop?
mutt
mutt el 30 de En. de 2013
I want to find out if there is a matrix approach which can outperform the for loop when the inputs are non-trivial

Iniciar sesión para comentar.

Respuesta aceptada

Oleg Komarov
Oleg Komarov el 30 de En. de 2013
You can use accumarray():
Y = [uniquedates accumarray(X(:,1),X(:,2))];
  3 comentarios
Oleg Komarov
Oleg Komarov el 30 de En. de 2013
Map the dates to a set X in the positive N, i.e. use unique on the dates and then X(:,1) is the ia index from the call to unique.
mutt
mutt el 31 de En. de 2013
This approach has delivered a 99% time saving versus the for loop.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by