matrix normalization in matlab

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jenifer
jenifer el 30 de En. de 2013
Editada: DGM el 11 de Dic. de 2022
hi.. i want normalize a matrix (129 x 128)..please help me with matlab codes

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Thorsten
Thorsten el 30 de En. de 2013
To normalize a matrix such that all values fall in the range [0, 1] use
Anorm = (A - min2(A))/(max2(A) - min2(A));
  3 comentarios
Irawati Roy
Irawati Roy el 11 de Dic. de 2022
You missed a dot before the division operation for a 2d matrix
DGM
DGM el 11 de Dic. de 2022
Editada: DGM el 11 de Dic. de 2022
There ./ is not needed here, since the denominator is a scalar.
That said, there is no function called min2() or max2(), nor can I find evidence that there were functions by those names which have since been removed. Maybe they used to be part of one of the toolboxes.
Alternatively, you could do:
Anorm = (A - min(A(:)))/(max(A(:)) - min(A(:)));
or you could do
Anorm = (A - min(A,[],'all'))/(max(A,[],'all') - min(A,[],'all'));
though the latter option wouldn't have worked circa 2013

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Más respuestas (3)

Matt J
Matt J el 30 de En. de 2013
You need to decide how you want to define the amplitude of the matrix first. Maybe you want this
normalized = A/norm(A);
or maybe this
normalized = A/max(abs(A(:)))
  3 comentarios
jenifer
jenifer el 30 de En. de 2013
ya... but how can i get a single value from whole matrix...
Jan
Jan el 30 de En. de 2013
Please, jenifer, we have asked you to define "normalization" exactly. It wastes time if we guess what you mean.

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Jing
Jing el 30 de En. de 2013
You can use 'normc' or 'normr' for normalization. 'c' or 'r' stands for columns or rows that you want to normalize.

DGM
DGM el 11 de Dic. de 2022
Since R2018a, you can use normalize() to perform normalization in various different ways.
A = 1:6
A = 1×6
1 2 3 4 5 6
B1 = normalize(A,'range') % default range is [0 1]
B1 = 1×6
0 0.2000 0.4000 0.6000 0.8000 1.0000
B2 = normalize(A,'range',[-1 2]) % but you can specify any range
B2 = 1×6
-1.0000 -0.4000 0.2000 0.8000 1.4000 2.0000
B3 = normalize(A,'zscore','std') % zero-center and scale to have std=1
B3 = 1×6
-1.3363 -0.8018 -0.2673 0.2673 0.8018 1.3363
B4 = normalize(A,'norm',2) % normalize by vector p-norm (default p=2)
B4 = 1×6
0.1048 0.2097 0.3145 0.4193 0.5241 0.6290

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