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Plotting the tone frequencies

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Anonym
Anonym el 4 de Oct. de 2020
Comentada: Star Strider el 7 de Dic. de 2020
I am in the process of creating sound. I've created the tone frequencies, but I'll need to show it on a diagram (ex. plot), but it keep giving me error, when using the:
plot(s1+s2);
What am I doing wrong?
The two first plots doesn't give any results, it's just blue.
figure
subplot(3,1,1);
plot(t, s1);
xlim([0 1E+3]);
grid
subplot(3,1,2);
plot(t, s2);
xlim([0 1E+3]);
grid
subplot(3,1,3);
plot(t, s1 + s2);
xlim([0 1E+3]);
grid
  2 comentarios
Cris LaPierre
Cris LaPierre el 4 de Oct. de 2020
It's always helpful to share the full error message as well.
When I run the code you shared with the plot command at the end, it generates a warning, but the plot appears. Is that what you see?
Anonym
Anonym el 4 de Oct. de 2020
Editada: Anonym el 4 de Oct. de 2020
Updated the thread.
Yes sorry, I meant there wasn't something inside the plot, when the window pop-up. It was only blue inside.

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Star Strider
Star Strider el 4 de Oct. de 2020
Note that ‘t’ seems to be missing.
Substituting for it and changing the xlim parameters:
t = values;
figure
subplot(3,1,1);
plot(t, s1);
xlim([0 1E-1]);
grid
subplot(3,1,2);
plot(t, s2);
xlim([0 1E-1]);
grid
subplot(3,1,3);
plot(t, s1 + s2);
xlim([0 1E-1]);
grid
appears to create two separate tones and a modulated summation.
It is necessary to ‘zoom’ the plots this way in order to see the details.
  13 comentarios
Anonym
Anonym el 7 de Dic. de 2020
Hello, sorry for always disturbing you. Do not know who else I could ask. There is just one thing I am curious about regarding this; is that how can I analyze a graph a two-tone frequencies that are combined in a graph? By your help and using your assistance, I have created two pairs of two frequencies with a close frequency and one with two frequencies that are far apart from each other. There is a clear difference, but how can we analyze it directly from the graph?
Appreciating your help.
Star Strider
Star Strider el 7 de Dic. de 2020
No worries.
I posted a sort-of Answer to it.

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