How to define a structure fieldname from a cell contains a string value?
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Dear All:
I am having trouble to define structure fieldnames from a cell array that contains the names as string values:
select = [{'NAME'}, {'VALUE'};
{'alpha'}, 0.4;
{'sigmaL'}, 1;
{'beta'}, 0.98];
and in a loop I want to create a structure from the cell array (select) with field name as in the first column and value in the second column if certain criteria is met. I have tried setfield and struct command, but in all cases the 'fieldname' input does not like I reference to the cell array (eg: select(1,3)), and ask for a proper string within quotation marks.
I want to ask how to create a structure by referencing to cell arrays? (In my case is create something like structure.alpha = 0.4 by referencing to select?)
Thank you very much in advance for your help.
Cheers
Ben
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Respuesta aceptada
Matt Fig
el 24 de Abr. de 2011
Instead of using EVAL, use dynamic fieldnames....
select = [{'NAME'}, {'VALUE'};
{'alpha'}, 0.4;
{'sigmaL'}, 1;
{'beta'}, 0.98];
for ii = 1:size(select,1)
S.(select{ii,1}) = select{ii,2};
end
Now you have a structure S. You might get a warning because the fieldname alpha is the same as the MATLAB function ALPHA. Note that using CELL2STRUCT is preferred here, as Oleg shows...
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Más respuestas (4)
Paulo Silva
el 23 de Abr. de 2011
select = [{'NAME'}, {'VALUE'};
{'alpha'}, 0.4;
{'sigmaL'}, 1;
{'beta'}, 0.98];
for a=2:size(select,1)
eval(sprintf('MyStruct.%s=%d',select{a,1},select{a,2}));
end
MyStruct
or
MyStruct=struct();
for a=2:size(select,1)
MyStruct=setfield(MyStruct, select{a,1}, select{a,2});
end
MyStruct
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Walter Roberson
el 23 de Abr. de 2011
struct(select{3,1}, select{3,2})
Remember, select(1,3) is the (non-existent) third column of the first row of the array select.
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