Annually averaging of a 4D matrix

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HA
HA el 12 de Oct. de 2020
Comentada: HA el 14 de Oct. de 2020
Hello,
I have a 4D data set (e.g. lon : lat : height : month) that I need to annually average. Usually with a 3D data set (e.g. lon : lat : month) I would use-
s=size(A);
B = squeeze(nanmean(reshape(A,[s(1:2),12,s(3)/12]),3));
For a 4D data set I have tried-
s=size(A);
B = squeeze(nanmean(reshape(A,[s(1:2:3),12,s(4)/12]),4));
I am guessing that I need to put something else in the square bracket or I am changing something wrong, but after trying various alterations I have decdied to ask the community.
Thank you.

Respuesta aceptada

Rik
Rik el 12 de Oct. de 2020
You are using the color operator incorrectly. 1:2:3 doesn't mean [1 2 3], but [1 3].
If your syntax does indeed work for you, the edit below should be what you're looking for.
s=size(A);
B = squeeze(nanmean(reshape(A,[s(1:3),12,s(4)/12]),4));
  1 comentario
HA
HA el 14 de Oct. de 2020
Aha, of course it does! Thank you, I can see how that is a silly mistake now!

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