Accessing 1 by n array from a cell array

The output of the following code is the cell array poh. Is there a way to instead access the first subarray {'poh',3,4.56} through a similar command and commands to find, for example, its size?

a=[{'poh',3,4.56},{'v',5}]
a{1}

Answer 1

[Star Strider]

The problem is that the square brackets [] concatenate the two cells to produce:

a =

  1×5 cell array

    {'poh'}    {[3.0000e+000]}    {[4.5600e+000]}    {'v'}    {[5.0000e+000]}

If you replace them with curly braces {}, ‘a’ becomes:

a =

  1×2 cell array

    {1×3 cell}    {1×2 cell}

and the result of

    a{1} 

is:

ans =

  1×3 cell array

    {'poh'}    {[3.0000e+000]}    {[4.5600e+000]}

as desired.

With that, you can then get:

Out = cellfun(@size, a, 'Uni',0)
Out{1}
Out{2}

producing:

ans =
     1     3

ans =
     1     2

EDIT — (12 Oct 2020 at 13:23)

Added example results.

.

[Aleem Andrew]

Thank you for your help

[Star Strider]

As always, my pleasure!