how to get the value of x, from this equation: 0.2exp(x)-x^(0.25) = 0

% I tried with the below steps:

fun = @(x) (0.2*exp(x)-x.^(0.25));
x0 = [1.5,0];
x = fsolve(fun,x0);

[Walter Roberson]

try 0,1.5 instead of 1.5,0

Answer 1

[Star Strider]

I do not understand what the problem is:

fun = @(x) (0.2*exp(x)-x.^(0.25));
x0 = [1.5,0];
x = fsolve(fun,x0);

xv = linspace(0,2);

figure
plot(xv, fun(xv))
hold on
plot(x, fun(x), 'rx')
hold off
grid

producing:

This appears to work, and provide the solutions you want.

Answer 2

[mike Croucher]

That seems to have done the job. I typed your commands and got

x =
    1.7492    0.0016

Substituting this into your function gives a vector of results extremely close to 0:

fun(x)
ans =
   1.0e-08 *
    0.0000    0.1948

Is this what you were hoping for?