Assign values of .mat files into matrix
18 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Tessa Kol
el 19 de Oct. de 2020
- silomodresults1.mat
- silomodresults2.mat
- silomodresults3.mat
- silomodresults4.mat
- silomodresults5.mat
- silomodresults6.mat
- silomodresults7.mat
- silomodresults8.mat
- silomodresults9.mat
- silomodresults10.mat
- silomodresults11.mat
- silomodresults12.mat
- silomodresults13.mat
- silomodresults14.mat
- silomodresults15.mat
- silomodresults16.mat
- silomodresults17.mat
- silomodresults18.mat
- silomodresults19.mat
- silomodresults20.mat
Dear all,
I have multiple .mat files (see attachment). I want to organize the MFR_mod variables within the those .mat files into one matrix. I feel like there is a smarter way then what I tried below. This will take me forever, since MFR_mod goes from 1 until 81.
for ii = 1:20
load(['silomodresults',num2str(ii),'.mat'])
end
MFR_tot = [MFR_mod1; MFR_mod2; MFR_mod3; MFR_mod4; MFR_mod5; MFR_mod6; MFR_mod7; MFR_mod8; MFR_mod9; MFR_mod10; MFR_mod11; MFR_mod12; MFR_mod13; MFR_mod14; MFR_mod15; MFR_mod16; MFR_mod17; MFR_mod18; MFR_mod19; MFR_mod20];
0 comentarios
Respuesta aceptada
Stephen23
el 19 de Oct. de 2020
Editada: Stephen23
el 19 de Oct. de 2020
D = 'path to the folder where the files are saved';
S = dir(fullfile(D,'silomodresults*.mat'));
C = {};
for k = 1:numel(S)
F = fullfile(D,S(k).name);
T = load(F,'-regexp','^MFR_mod\d+$');
N = fieldnames(T);
V = str2double(regexp(N,'\d+','once','match'));
C(V) = struct2cell(T); %#ok<SAGROW>
end
M = vertcat(C{:}); % optional
Giving:
>> size(M)
ans =
81 1
>> plot(M)
9 comentarios
Stephen23
el 20 de Oct. de 2020
You could define all of the indices before the loop:
idc = {1,2,3,4,[5,11,20,38,81],[12,15,31,55,65],...};
and then inside the loop you can replace that entire huge lbock of code
if i== ..
..
elseif i== ..
..
..
end
with just this:
idx = idc{ii};
fnm = sprintf('silomodresults%d.mat',ii);
save(fnm,'MFR_mod','rho_bmod','idx')
It is still a mystery to me, how those indices are defined.
Más respuestas (2)
Ameer Hamza
el 19 de Oct. de 2020
Editada: Ameer Hamza
el 19 de Oct. de 2020
One of the major problem is naming the variables like this x1, x2, ...: https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval. You can try something like this
MFR_tot = zeros(1, 20);
for ii = 1:20
data = load(['silomodresults',num2str(ii),'.mat']);
MFR_tot(ii) = data.(sprintf('MFR_mod%d', ii))
end
1 comentario
Mathieu NOE
el 19 de Oct. de 2020
hello
seems all your mat file contains the same size of data
so the modification of you r code is fairly simple - if I understand what you want :
MFR_tot = [];
for ii = 1:20
data = load(['silomodresults',num2str(ii),'.mat']);
MFR_tot = [MFR_tot; data]; % concatenation
end
3 comentarios
Mathieu NOE
el 19 de Oct. de 2020
ok , now I understand
is there any possibility for you to generate dummy mat files , but much smaller. I'd like to try to solve it
I think the key thing is to extract the field (variables) names and then re order the whole thing based on the numeric content of the variable name
That shoudn't be too difficult for someone fluent in string / structure processing (I don't mean me only !)
I'll give it a try tomorrow if you can send me some dummy mat files in between
Ver también
Categorías
Más información sobre Data Preprocessing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!