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Suggestion on what im doing wrong.
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I need to write a code that exclude the 2 smallest elements
clear all;clc
A=[8 1 -2 9 5 11 6]; %Should print A=[8 9 5 11 6]
B=[];
C=[];
for i=1:length(A)
if A(i)==min(A)
else
B=[B A(i)];
if A(i)==min(A)
else
C=[C A(i)];
end
end
end
C
This is a homework question and I am not looking for someone to do the work for me. I just need to know what I'm doing wrong.
So I just came up with this and I'm testing multiple numbers. Does it make sense and is there a way to simplify it?
clear all;clc
A=[8 1 -2 9 5 6];
B=[];
C=[];
for i=1:length(A)
if A(i)==min(A)
else
B=[B A(i)];
end
end
for i=1:length(B)
if B(i)==min(B)
else
C=[C B(i)];
end
end
C
So far it seems to work but I would appreciate any constructive input.
2 comentarios
Walter Roberson
el 22 de Oct. de 2020
What is the expected result if the vector contains duplicate values that are equal to the minimum? What is the expected result if the vector contains duplicate values that are equal to the second-smallest original value?
Can we assume that the values are non NaN (Not A Number)?
Respuestas (1)
Sudhakar Shinde
el 22 de Oct. de 2020
The 'min' function and for loop will help:
A=[8 1 -2 9 5 11 6];
n=2; % Exclude 2 smallest elements
for i=1:n
[num,id]=min(A);
A(id)='';
end
disp(A)
3 comentarios
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