char to double data type
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How do I convert the following
164x11 char=
'03-Jan-2018'
'07-Jan-2018'
'07-Jan-2018'..
to 164x11 double=
'03-Jan-2018'
'07-Jan-2018'
'07-Jan-2018'
I want the elements to remain the same and just change the data type
2 comentarios
Respuestas (2)
dpb
el 24 de Oct. de 2020
Deprecated (and not recommended) would be
dn=datenum(yourdatechararray,'dd-mmm-yyyy');
which, of course, returns the datenum associated with the date; to get the representation use datestr. But, dn is a double.
The present (and recommended) way to handle dates is to use datetime instead --
dt=datetime(yourdatechararray,'InputFormat','dd-MMM-yyyy');
NB: the input format string representations are NOT the same between the two.
dt is its own class of datetime array, not a double. But, one can do comparisons of equality, greater/less than, etc., as well as plot and such have been extended to recognize the class as inputs.
4 comentarios
Walter Roberson
el 24 de Oct. de 2020
fprintf() or compose() -- you will probably find compose() easier.
Steven Lord
el 24 de Oct. de 2020
I recommend turning the character data representing dates into a datetime array and using that datetime array along with your double data to create a timetable.
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