Matlab returns empty symbol when solving laplace transform

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Richard Baird
Richard Baird el 24 de Oct. de 2020
Comentada: Star Strider el 26 de Oct. de 2020
I have a laplace equation defined in matlab that I believe to be correct. It is defined as eqnLT
% R1, R2, C1, C2 are positive symbols
% i(t) is a symbolic function
% i(0) is set to be 0
eqn(t) =
0 == R1*i(t) + R2*i(t) + diff(i(t), t)/10 + int(i(t), t)/C1 + int(i(t), t)/C2
eqnLT = laplace(eqn, t, s) =
0 == (s*laplace(i(t), t, s))/10 - i(0)/10 + laplace(int(i(t), t), t, s)/C1 + laplace(int(i(t), t), t, s)/C2 + R1*laplace(i(t), t, s) + R2*laplace(i(t), t, s)
I want to solve for `laplace(i(t), t, s)` let it be called `I(s)`. Following the instructions I can find in the matlab documentation, I do the following:
subs(eqnLT, laplace(i(t),t,s),I(s)));
solve(eqnLT, I(s))
The answer I get is empty sym. I am not sure what I am doing wrong.

Respuestas (1)

Star Strider
Star Strider el 24 de Oct. de 2020
Try this:
syms s t C1 C2 R1 R2 i(t) I(s)
eqn(t) = 0 == R1*i(t) + R2*i(t) + diff(i(t), t)/10 + int(i(t), t)/C1 + int(i(t), t)/C2
eqnLT = laplace(eqn, t, s)
eqnLT = 0 == (s*laplace(i(t), t, s))/10 - i(0)/10 + laplace(int(i(t), t), t, s)/C1 + laplace(int(i(t), t), t, s)/C2 + R1*laplace(i(t), t, s) + R2*laplace(i(t), t, s)
eqnLT = subs(eqnLT, {laplace(i(t), t, s), laplace(int(i(t), t), t, s)}, {I(s), I(s)/s})
isoI = simplify(isolate(eqnLT,I), 'Steps',500)
Experiment with it to get the result you want (works in R2020b, Update 1).
  2 comentarios
Richard Baird
Richard Baird el 26 de Oct. de 2020
That worked. Thank you!
Star Strider
Star Strider el 26 de Oct. de 2020
My pleasure!
If my Answer helped you solve your problem, please Accept it!
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