How to convert a vector of integers to a vector of characters?

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Hi - I have a vector of ints, typically 0/1, like this:
[0 0 0 0 1 0 0 0 0 1]
and I want to get this:
['0' '0' '0' '0' '1' '0' '0' '0' '0' '1']
But I cannot figure it out for the life of me. I'm sure it's simple. Thanks for your time and help.

Respuesta aceptada

James Tursa
James Tursa el 10 de Feb. de 2013
Another method for single digits:
A = [0 0 0 0 1 0 0 0 0 1];
B = char(A+'0');

Más respuestas (3)

Wayne King
Wayne King el 9 de Feb. de 2013
Editada: Wayne King el 9 de Feb. de 2013
A = [0 0 0 0 1 0 0 0 0 1];
B = num2str(A);
Now B is a vector of characters
  2 comentarios
Michael
Michael el 9 de Feb. de 2013
Hi Wayne -- I knew of num2str and tried that, but it turns out you're right. But what I figured out was that it was the extra spaces in the result of num2str that was throwing me off. i.e. num2str([0 0 0 0 0]) = '0 0 0 0 0', which is length 9 or something (but not 5). I removed the spaces from the result of num2str and it worked great. Thanks for the help.

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Azzi Abdelmalek
Azzi Abdelmalek el 9 de Feb. de 2013
Editada: Azzi Abdelmalek el 9 de Feb. de 2013
a = [0 0 0 0 1 0 0 0 0 1];
y=arrayfun(@(x) cellstr(num2str(x)),a)
% To get any character
y{4} % for e.g

Jan
Jan el 10 de Feb. de 2013
Editada: Jan el 10 de Feb. de 2013
Instead of removing the spaces from the output of num2str, you can create string without spaces directly:
a = [0 0 0 0 1 0 0 0 0 1];
s = sprintf('%d', a);
Another fast but more strange method is:
s = char('0' + a);

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