Calculate the energy of the signal, find odd and even component and then plot it.

2 visualizaciones (últimos 30 días)
This is what my teacher have told to me.
ONLY HOW TO CLACULATE ENERGY.
clc
clear all
close all
syms x t
x=exp(-2.^t);
z=x^2;
Energy=int(z,t,0,inf);
disp(Energy)
also want to plot the expnonential function, how can i do that for the above code?
This is what i have done.
clc
close all
clear all
%FOR ENERGY
t= 0:0.09:10;
p= -2.*t;
x= exp(p);
energy= 1/(2*2) % if e^-at is an energy signal⇒ energy = 1/2*a
subplot(2,1,1)
plot(t,x)
text(5,0.4, ['Energy Of The Signal =', num2str(energy)])
xlabel('time->')
ylabel('x(t)')
title('Plot For x(t)')
grid on
gtext('1841014009')
% FOR EVEN AND ODD COMPONENT
p2= -2.*-t;
x2= exp(p2);
xe= (x+x2)/2; % FOR EVEN
xo= (x-x2)/2; %FOR ODD
subplot(2,1,2);
plot(t,xe,'r')
hold on
plot(t,xo,'b')
legend ('EVEN','ODD')
xlabel('time->')
ylabel('x(t)')
grid on
gtext('1841014009')
please help me......
which one is the correct answer, first one or second one?
OR
both are wrong.

Respuesta aceptada

VBBV
VBBV el 31 de Oct. de 2020
Editada: VBBV el 31 de Oct. de 2020
% if true
% code
% end
clc
syms x t
close all
x=exp(-2*t);
z=@(x) x.^2;
Energy=integral(z,0,inf);
%plot odd and even signals
t = 0:0.1:20;
x = exp(-2.*t);
xx = exp(-2.*-t);
xe= (x+xx)./2;
xo = (x-xx)./2;
plot(t,xo,'b',t,xe);legend('odd','even');
  1 comentario
Suraj Narayan
Suraj Narayan el 31 de Oct. de 2020
Editada: Suraj Narayan el 31 de Oct. de 2020
Thanks for the help.
Could you please explain in more detail about the integral part
And is it possible to plot the signal.

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