is there any correction..?
Mostrar comentarios más antiguos
I am doing Singular value decomposition using this.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
[U S V] = svd(A)
Now, i want to do the same without function. so, i written little as below.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
f = eig(A'*A);
for l = 1:length(f);
p(l) = sqrt(f(l));
end
S = diag(p);
[U,D] = eig(A*A');
[V,D] = eig(A'*A);
V = V';
U
S
But in answer i am getting only some of its elements same in matrix. And remaining are different. So, please suggest any modification if there or solution..?
Respuestas (1)
Walter Roberson
el 20 de Feb. de 2013
0 votos
In your second bit of code, your S is a square diagonal matrix, not a diagonal matrix the same size as A.
1 comentario
Lalit Patil
el 20 de Feb. de 2013
Editada: Lalit Patil
el 21 de Feb. de 2013
Categorías
Más información sobre Creating and Concatenating Matrices en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!