# About Choosing MATRIX element

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Onur Turan on 13 Nov 2020
Answered: Deepak Meena on 17 Nov 2020
function[Ybus] = ybus(zdata) %first function
nl=zdata(:,1); nr=zdata(:,2); R=zdata(:,3); X=zdata(:,4);
nbr=length(zdata(:,1)); nbus = max(max(nl), max(nr));
Z = R + j*X;
y= ones(nbr,1)./Z;
Ybus=zeros(nbus,nbus);
for k = 1:nbr;
if nl(k) > 0 & nr(k) > 0
Ybus(nl(k),nr(k)) = Ybus(nl(k),nr(k)) - y(k);
Ybus(nr(k),nl(k)) = Ybus(nl(k),nr(k));
end
end
for n = 1:nbus
for k = 1:nbr
if nl(k) == n | nr(k) == n
Ybus(n,n) = Ybus(n,n) + y(k);
else, end
end
end
% From To R X ---these are from circuit second function
z = [ 1 2 0.12 0.16
2 3 0.032 0.012
3 4 0.001 0.1
3 5 0.002 0.015];
[Ybus] = ybus(z) % bus admittance matrix
Hello,
I would like to choose every element of a matrix with for loop. I mean first I need to select 1st. element then I need to save it to a variable. Then second. thirt... etc.
The matrix that I mention has real and imaginer side in every element. Like;
[Ybus] = ybus(z) % bus admittance matrix
YBara =
3.0000 - 4.0000i -3.0000 + 4.0000i 0.0000 + 0.0000i 0.0000 + 0.0000i 0.0000 + 0.0000i
-3.0000 + 4.0000i 30.3973 -14.2740i -27.3973 +10.2740i 0.0000 + 0.0000i 0.0000 + 0.0000i
0.0000 + 0.0000i -27.3973 +10.2740i 36.2309 -85.7752i -0.1000 + 9.9990i -8.7336 +65.5022i
0.0000 + 0.0000i 0.0000 + 0.0000i -0.1000 + 9.9990i 0.1000 - 9.9990i 0.0000 + 0.0000i
0.0000 + 0.0000i 0.0000 + 0.0000i -8.7336 +65.5022i 0.0000 + 0.0000i 8.7336 -65.5022i
Who can help me? Thank you.
REgards.

Deepak Meena on 17 Nov 2020
Hi,
I think you want to know how you acces the array elements in a for loop. You can refer to this documentations: