Remove rows or cols whose elements are all NaN
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Jeon
el 25 de Mzo. de 2013
Comentada: Andrew Sol
el 14 de Nov. de 2024 a las 7:43
How can I remove rows or cols whose elements are all NaN ? Withouot any dirty iterations?
For example,
A = [1 1 1 1 1 1 1 1 1 1;
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN;
1 1 1 1 1 1 1 1 1 1;
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN;];
should turned into
A = [1 1 1 1 1 1 1 1 1 1;
1 1 1 1 1 1 1 1 1 1];
This is just an example. Actually I have a very big matrix. So I want a solution of this question to work well with my big matrix.
2 comentarios
Respuesta aceptada
Andrei Bobrov
el 25 de Mzo. de 2013
Editada: Andrei Bobrov
el 25 de Mzo. de 2013
out = A(all(~isnan(A),2),:); % for nan - rows
out = A(:,all(~isnan(A))); % for nan - columns
5 comentarios
Céldor
el 2 de Abr. de 2015
Can I obtain a logical matrix I of indices to be held / removed something like
I = something here
and then use assign an altered matrices:
out1 = out1(I);
out2 = out2(I);
% ... etc.
Thanks
gringer45
el 18 de Mzo. de 2018
This doesn't really do what the question asks for. This selects all the columns or rows with none (zero) NaN values. So, this is answering the question: "Remove rows or cols whose elements have any (at least one) NaN"
Más respuestas (6)
Phillippe
el 14 de En. de 2015
To remove only ALL-NaN columns, do this instead:
A = A(:,~all(isnan(A)));
4 comentarios
Azzi Abdelmalek
el 25 de Mzo. de 2013
A(isnan(A))=[]
6 comentarios
Walter Roberson
el 28 de Mayo de 2020
A(all(isnan(A),2),:) = []; %rows that are all nan
A(:, all(isnan(A),1)) = []; %cols that are all nan
Alfaz Memon
el 20 de Ag. de 2018
Editada: Alfaz Memon
el 21 de Ag. de 2018
input varibale : data
output variable : row_index( index of rows with all the value as NaN)
row_index( index of rows with all the value as NaN)
column_index( index of columns with all the value as NaN)
if(iscell(data))
x =find(cell2mat((cellfun(@(data) any(isnan(data),2),data,'UniformOutput',false))));
[ia,ib] = ind2sub(size(data),x);
rows_unique = unique(ia);
rows_unique(:,2)=histc(ia,rows_unique);
row_index = rows_unique(find(rows_unique(:,2)==size(data,2)),1);
columns_unique = unique(ib);
columns_unique(:,2)=histc(ib,columns_unique);
column_index = rows_unique(find(columns_unique(:,2)==size(data,1)),1);
else
row_index =find(~any(~isnan(data), 2)); % row with all NaN values
column_index =find(~any(~isnan(data), 1)); %column with all NaN values
end
2 comentarios
Walter Roberson
el 20 de Ag. de 2018
Seems like a bit of a bother to just remove the rows or columns ?
I notice that you are using cellfun on the data, implying that the data is a cell array; in the original question it was a plain array.
Alfaz Memon
el 21 de Ag. de 2018
Editada: Alfaz Memon
el 21 de Ag. de 2018
yeah its for cell array. for plain array you can remove cellfun and just simply keep any(isnan(data),2) instead of x =find(cell2mat((cellfun(@(data) any(isnan(data),2),data,'UniformOutput',false))));
this can you work for cell array of different data type.
Also I have updated solution.
Ilham Hardy
el 25 de Mzo. de 2013
Haven't tried this, but it should works:
A(isnan(A))=[];
1 comentario
Jan
el 25 de Mzo. de 2013
This does not solve the wanted: "delete rows or cols whose elements are all NaN"
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