Remove rows or cols whose elements are all NaN

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Jeon
Jeon el 25 de Mzo. de 2013
Comentada: Andrew Sol el 14 de Nov. de 2024 a las 7:43
How can I remove rows or cols whose elements are all NaN ? Withouot any dirty iterations?
For example,
A = [1 1 1 1 1 1 1 1 1 1;
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN;
1 1 1 1 1 1 1 1 1 1;
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN;];
should turned into
A = [1 1 1 1 1 1 1 1 1 1;
1 1 1 1 1 1 1 1 1 1];
This is just an example. Actually I have a very big matrix. So I want a solution of this question to work well with my big matrix.
  2 comentarios
Dev-iL
Dev-iL el 13 de Jul. de 2014
Editada: Dev-iL el 13 de Jul. de 2014
Hi! You can find some clues here: A discussion of the opposite problem on SE. I personally achieved what you were attempting using:
A(~any(~isnan(A), 2),:)=[];
Walter Roberson
Walter Roberson el 20 de Sept. de 2015
Michal Gajewski commented
works

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Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 25 de Mzo. de 2013
Editada: Andrei Bobrov el 25 de Mzo. de 2013
out = A(all(~isnan(A),2),:); % for nan - rows
out = A(:,all(~isnan(A))); % for nan - columns
  5 comentarios
Céldor
Céldor el 2 de Abr. de 2015
Can I obtain a logical matrix I of indices to be held / removed something like
I = something here
and then use assign an altered matrices:
out1 = out1(I);
out2 = out2(I);
% ... etc.
Thanks
gringer45
gringer45 el 18 de Mzo. de 2018
This doesn't really do what the question asks for. This selects all the columns or rows with none (zero) NaN values. So, this is answering the question: "Remove rows or cols whose elements have any (at least one) NaN"

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Más respuestas (6)

Phillippe
Phillippe el 14 de En. de 2015
To remove only ALL-NaN columns, do this instead:
A = A(:,~all(isnan(A)));
  4 comentarios
Parth Dev Bundela
Parth Dev Bundela el 22 de Oct. de 2022
Thanks man
osman alper altun
osman alper altun el 14 de Feb. de 2023
Thank you!

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Saman
Saman el 23 de Oct. de 2013
Editada: Saman el 23 de Oct. de 2013
Use this :
out = A(:,any(~isnan(A))); % for columns
out = A(any(~isnan(A),2),:); %for rows

Azzi Abdelmalek
Azzi Abdelmalek el 25 de Mzo. de 2013
A(isnan(A))=[]
  6 comentarios
Walter Roberson
Walter Roberson el 28 de Mayo de 2020
A(all(isnan(A),2),:) = []; %rows that are all nan
A(:, all(isnan(A),1)) = []; %cols that are all nan
Andrew Sol
Andrew Sol el 14 de Nov. de 2024 a las 7:43
You proposed too simple a solution and you were wrong.

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Alfaz Memon
Alfaz Memon el 20 de Ag. de 2018
Editada: Alfaz Memon el 21 de Ag. de 2018
input varibale : data
output variable : row_index( index of rows with all the value as NaN)
row_index( index of rows with all the value as NaN)
column_index( index of columns with all the value as NaN)
if(iscell(data))
x =find(cell2mat((cellfun(@(data) any(isnan(data),2),data,'UniformOutput',false))));
[ia,ib] = ind2sub(size(data),x);
rows_unique = unique(ia);
rows_unique(:,2)=histc(ia,rows_unique);
row_index = rows_unique(find(rows_unique(:,2)==size(data,2)),1);
columns_unique = unique(ib);
columns_unique(:,2)=histc(ib,columns_unique);
column_index = rows_unique(find(columns_unique(:,2)==size(data,1)),1);
else
row_index =find(~any(~isnan(data), 2)); % row with all NaN values
column_index =find(~any(~isnan(data), 1)); %column with all NaN values
end
  2 comentarios
Walter Roberson
Walter Roberson el 20 de Ag. de 2018
Seems like a bit of a bother to just remove the rows or columns ?
I notice that you are using cellfun on the data, implying that the data is a cell array; in the original question it was a plain array.
Alfaz Memon
Alfaz Memon el 21 de Ag. de 2018
Editada: Alfaz Memon el 21 de Ag. de 2018
yeah its for cell array. for plain array you can remove cellfun and just simply keep any(isnan(data),2) instead of x =find(cell2mat((cellfun(@(data) any(isnan(data),2),data,'UniformOutput',false))));
this can you work for cell array of different data type.
Also I have updated solution.

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Ilham Hardy
Ilham Hardy el 25 de Mzo. de 2013
Haven't tried this, but it should works:
A(isnan(A))=[];
  1 comentario
Jan
Jan el 25 de Mzo. de 2013
This does not solve the wanted: "delete rows or cols whose elements are all NaN"

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Nike
Nike el 25 de Mzo. de 2013
Simplest is
A(isnan(A))= [];
  1 comentario
Jan
Jan el 25 de Mzo. de 2013
This has been posted twice already. But it still does not solve the original question:
delete rows or cols whose elements are all NaN
For e.g. A = [1, NaN, 1; NaN, 1, NaN] nothing should be deleted.

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