how to use transformation with fminunc

3 visualizaciones (últimos 30 días)
Saad
Saad el 30 de Mzo. de 2013
Dear all,
I am replicating a paper who recommends using fminunc to do a "constrained" optimization through a transformation. I have tried to use directly fmincon (with different algorithms) but the function doesnt optimize, thats the reason I would like to follow the paper advice and use a transformation as follows:
C_bar = lamda*(exp(C)/1+ exp(C))
where lamda is a constant, C is the unconstrained variable and C_bar is the constrained variable. I would really appreciate if you could show me how I could use the transformation in matlab. Do I have to create a seperate function? How can I link it to the optimizer please?
Here is my code
C=[1; 1; 1 ; 1; 1; 1; 1; 1; 1];
options=optimset('Diagnostics','on','Display','iter','TolX',0.001,'TolFun',0.001,'LargeScale','off','HessUpdate','bfgs');
[beta,fval,exitflag,output,grad,hessian] =fminunc(@mll,C,options)
Thanks a lot for your help
Best Regards
SB
  2 comentarios
Matt J
Matt J el 31 de Mzo. de 2013
Editada: Matt J el 31 de Mzo. de 2013
Do you really mean
C_bar = lamda*exp(C)/(1+ exp(C))
Saad
Saad el 31 de Mzo. de 2013
Sorry I did miss a parenthese, it is actually
C=lamda* (exp(C)/(1+ exp(C)));

Iniciar sesión para comentar.

Respuesta aceptada

Matt J
Matt J el 31 de Mzo. de 2013
Cbar=@(C) lamda*exp(C)/(1+ exp(C));
fminunc(@(C) mll(Cbar(C)) ,C,options)
  3 comentarios
Matt J
Matt J el 31 de Mzo. de 2013
Probably because of
'TolX',0.001,'TolFun',0.001
These look like very generous tolerances.
Saad
Saad el 31 de Mzo. de 2013
thats true. I will tighten the tolerances a bit and see if it helps the optimizer. Thanks Matt

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Quadratic Programming and Cone Programming en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by