I'm getting the error "Array indices must be positive integers or logical values." and it seems like I structures the for loop to handle the equations. Can anyone help me with this?
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Matthew Williams
el 13 de Dic. de 2020
Respondida: Gouri Chennuru
el 16 de Dic. de 2020
ds=zeros(length(y),1);
dAs=zeros(length(y),1);
Ac=zeros(length(y),1);
for j=1:N
t1=(t(y(j))+t(y(j+1/2)))/2; %average thickness of CV on side closer to y=0
t2=(t(y(j-1/2))+t(y(j)))/2; %avgerage thickness of CV on side closer to y=L
ds(j)=sqrt((t(y(j+1))-t(t(j-1))).^2+(2*dy).^2)/2; %using central difference
dAs(j)= (w+((t1+t2)/L))*ds(j)*dx; %surface area
Ac(j)=(t(y(j)))*dx; %Cross sectional area
end
3 comentarios
Walter Roberson
el 13 de Dic. de 2020
You cannot index at half-integers . You can index a value and divide the result by 2, though.
Respuesta aceptada
Gouri Chennuru
el 16 de Dic. de 2020
Hi Matthew,
As per my understanding, you are trying to extract the variable "y" with indices (j+1/2) and (j-1/2), from the following lines.
t1=(t(y(j))+t(y(j+1/2)))/2;
t2=(t(y(j-1/2))+t(y(j)))/2;
You cannot point arrays to a particular decimal index.As a workaround make sure that array Index is always a positive integer or a logical value.
Regards,
Gouri Chennuru
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