Fin heat transfer Matrix

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Yogesh Bhambhwani
Yogesh Bhambhwani el 16 de Dic. de 2020
Editada: Alan Stevens el 17 de Dic. de 2020
I need help solving this matrix with the equations given to me:
For the first node: T_1 = T_b
for the internal nodes: (T_2,T_3,T_4) = -T_i-1 +(2+(mdeltax)^2)T_i - Ti+1 = (mdeltax)^2T_inf
for the 5th node: -T_4 + (1+((mdeltax)^2/2))T_5 = ((mdeltax)^2/2)T_inf
where m = sqrt((hp)/(KA_c))
T_inf = 900 degrees celsius
T_b = 400 degress celsius
also have to compare the matrix solution to:
T_analytic = (cosh(m(L-x))/cosh(mL))*(T_b-T_inf)+T_inf
I need some help with the matrix solution.
  1 comentario
Ive J
Ive J el 17 de Dic. de 2020
Share with us what you've tried so far and clearly explain how do you want to solve this heat transfer equation in particular?

Iniciar sesión para comentar.

Respuesta aceptada

Alan Stevens
Alan Stevens el 17 de Dic. de 2020
Editada: Alan Stevens el 17 de Dic. de 2020
% Construct the matrix
% M = [ 1 0 0 0 0;
% -1 (2+(m*dx)^2) -1 0 0;
% 0 -1 (2+(m*dx)^2) -1 0;
% 0 0 -1 (2+(m*dx)^2) -1;
% 0 0 0 -1 (2+(m*dx)^2)/2];
%
% and the column vector
% K = [T_b;
% (m*dx)^2*T_inf;
% (m*dx)^2*T_inf;
% (m*dx)^2*T_inf;
% (m*dx)^2/2*T_inf];
%
% then you have the matrix equation M*T = K
% where T is a column vector of values of T_1; T_2 ...T_5
% and you can solve for T using T = M\K (notice the backslash
% not forward slash)

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