Interpolation incase on nan

I have a data which includes nans and I used interp1 to interpolate the data points, but error message is popping up which says it's not appropriate .Can anyone help me solving this?

Answer 1

[Jan]

No, currently I can't help. Please post some relevant example data (by editing the original question, not as comment or answer), such that we can see, which of the inputs contains the NaNs and where.

Then an answer will be easy (or impossible): Most likely the NaNs can be simply removed before the interpolation.

[EDITED after your first comment]

Had  = [1 3 4 6 nan nan 20 ];
time = [1 2 3 4 5 6 7];
good = ~isnan(Had);
had2 = [ 2.5 5 17]
time2= interp1(Had(good), time(good)', had2);

[Ede gerlderlands]

The data contains long series which can be shortened as;

Had= [1 3 4 6 nan nan 20 ]

time =[1 2 3 4 5 6 7]

had2= [ 2.5 5 17]

time2= interp1(Had,time',had2);

[Jan]

Ok, and what do you want as result? As long as you actually do not have a measurement at time=5:6, wouldn't this be a trivial solution: See [EDITED]