Borrar filtros
Borrar filtros

Solving Equations in MATLAB

1 visualización (últimos 30 días)
trythisone noone
trythisone noone el 27 de Dic. de 2020
Comentada: Ameer Hamza el 28 de Dic. de 2020
Hello,
I have the following equation.
cos(x) == 0
I want to get two or more possible solutions for the above equation which are 90, 270, and so on. The solve function returns the first solution only.
This technique is important for me to calculate the antenna beamwidths. Any ideas?
Thanks in Adv

Respuesta aceptada

Ameer Hamza
Ameer Hamza el 27 de Dic. de 2020
Editada: Ameer Hamza el 27 de Dic. de 2020
There is no general solution to such a problem. A common way is to specify several starting points for the numerical solver and find the unique solutions.
y = @(x) cos(x);
x_range = 0:0.1:4*pi;
y_sol = zeros(size(x_range));
for i = 1:numel(x_range)
y_sol(i) = fzero(y, x_range(i));
end
y_sol = uniquetol(y_sol)
  2 comentarios
trythisone noone
trythisone noone el 27 de Dic. de 2020
Wow, Nice trick man. It works fine. <3
Ameer Hamza
Ameer Hamza el 28 de Dic. de 2020
I am glad to be of help!

Iniciar sesión para comentar.

Más respuestas (1)

John D'Errico
John D'Errico el 27 de Dic. de 2020
SOME problems can be handled to find all solutions.
syms x
>> xsol = solve(cos(x) == 0,'returnconditions',true)
xsol =
struct with fields:
x: [1×1 sym]
parameters: [1×1 sym]
conditions: [1×1 sym]
>> xsol.parameters
ans =
k
>> xsol.conditions
ans =
in(k, 'integer')
>> xsol.x
ans =
pi/2 + pi*k
So we learn the set of all solutions takes the form
x = pi/2 + pi*k
where k is an integer.
Sadly, a fully general solution to many problems will not be written so easily. But you can always try.

Etiquetas

Productos


Versión

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by