To find intersection point of two lines?
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x1=7.8;
x2=8.5;
y1=0.96;
y2=0.94;
p1 = polyfit([x1 x2], [y1 y2], 2);
b1= polyval(p1,1);
m1=polyval(p1,2)-b1;
x3=8.25;
x4=8.25;
y3=0;
y4=.99;
p2 = polyfit([x3 x4], [y3 y4], 2);
b2 = polyval(p2, 1);
m2 = polyval(p2, 2) - b2;
I got x value = -1.2867; from which co-ordinate this value corresponds to? Actually I want to compute intersection of two line with respect to x=[7.8 8.25 8.5]; y=[0.96 0.99 0.94]; over which those two lines are plotted?
x=[7.8 8.25 8.5];
y=[0.96 0.99 0.94];
p=polyfit(x,y,2);
f=polyval(p,x);
plot(x,y,'o',x,f,'-');
hold on;
line([7.8 8.5],[0.96 0.94]);
hold on;
line([8.25 8.25],[0 0.99]);
2 comentarios
Image Analyst
el 7 de Abr. de 2013
Editada: Image Analyst
el 7 de Abr. de 2013
Do you want to do it numerically (using quantized arrays), or analytically (using algebraic equations)? Why did you tag this as digital image processing?
RS
el 27 de Abr. de 2013
Respuesta aceptada
Más respuestas (0)
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Más información sobre Image Arithmetic en Centro de ayuda y File Exchange.
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