Matrix dimensions must agree.

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Muhammad Ezree Amree bin Amran
Muhammad Ezree Amree bin Amran el 4 de En. de 2021
Comentada: Alan Stevens el 4 de En. de 2021
Hello everyone, can you please help me with this problem? I currently in my project's for Iterative Method. But I can't run the coding because of this problem.
P=(Lamda-beta)./(gamma*2);
Attached below is my full coding, can you guys help me?
clear clc;
% n all alpha beta gamma min max
d=[1 550 8.1000 0.00028 0 680
2 309 8.1000 0.00056 0 360
3 307 8.1000 0.00056 0 360
4 240 7.7400 0.00324 60 180
5 240 7.7400 0.00324 60 180
6 240 7.7400 0.00324 60 180
7 240 7.7400 0.00324 60 180
8 240 7.7400 0.00324 60 180
9 240 7.7400 0.00324 60 180
10 126 8.6000 0.00284 40 120
11 126 8.6000 0.00284 40 120
12 126 8.6000 0.00284 55 120
13 126 8.6000 0.00284 55 120];
Pd=1800; %Pdemand alpha=d(:,2);
n=d(:,1);
beta=d(:,3);
gamma=d(:,4);
Pmin=d(:,5);
Pmax=d(:,6);
DelP=Pd; i=1;
Iteration=i;
Lamda=8.35; % assume lambda L(i,1)=Lamda;
while abs(DelP)> 0.00001
P=(Lamda-beta)./(gamma*2);
P=min(P,Pmax); %p=ph if pmax<p//p>pmax //pick pmax bila pmax kecil dri p
P=max(P,Pmin); %p=pl if pmin>p//p<pmin
DelP=Pd-sum(P); Lamda=Lamda+DelP/(sum(1./(2*gamma)));
costI(:,i)=alpha+(beta.*P)+(gamma.*P.*P);
totalCost_iteration(i,1)=sum(costI(:,i));
Iteration(i,1)=i;
Lamda(i,1)=Lamda;
i=i+1;
end
Cost=alpha+(beta.*P)+(gamma.*P.*P); % Costs totalCost=sum(Cost);
totalPower=sum(P); table(d(:,1),P,Cost,'V',{'Unit' 'Power' 'Cost'})
display(totalCost);
display(totalPower);
figure
plot(Iteration,totalCost_iteration)
title('Convergest Graph')
xlabel('Number of Iteration')
ylabel('Cost(RM/h)')

Respuesta aceptada

Alan Stevens
Alan Stevens el 4 de En. de 2021
This works
% n all alpha beta gamma min max
d=[1 550 8.1000 0.00028 0 680
2 309 8.1000 0.00056 0 360
3 307 8.1000 0.00056 0 360
4 240 7.7400 0.00324 60 180
5 240 7.7400 0.00324 60 180
6 240 7.7400 0.00324 60 180
7 240 7.7400 0.00324 60 180
8 240 7.7400 0.00324 60 180
9 240 7.7400 0.00324 60 180
10 126 8.6000 0.00284 40 120
11 126 8.6000 0.00284 40 120
12 126 8.6000 0.00284 55 120
13 126 8.6000 0.00284 55 120];
Pd=1800; %Pdemand
alpha=d(:,2); %%%%%%%%%%%%%%
n=d(:,1);
beta=d(:,3);
gamma=d(:,4);
Pmin=d(:,5);
Pmax=d(:,6);
DelP=Pd; i=1;
Iteration=i;
Lamda=8.35; % assume lambda L(i,1)=Lamda;
while abs(DelP)> 0.00001
P=(Lamda-beta)./(gamma.*2);
P=min(P,Pmax); %p=ph if pmax<p//p>pmax //pick pmax bila pmax kecil dri p
P=max(P,Pmin); %p=pl if pmin>p//p<pmin
DelP=Pd-sum(P); Lamda=Lamda+DelP/(sum(1./(2*gamma)));
costI(:,i)=alpha+(beta.*P)+(gamma.*P.*P);
totalCost_iteration(i,1)=sum(costI(:,i));
Iteration(i,1)=i;
% Lamda(i,1)=Lamda; % This causes a problem during the iterations
i=i+1;
end
Cost=alpha+(beta.*P)+(gamma.*P.*P); % Costs
totalCost=sum(Cost); %%%%%%%%%%%%%%%%%%%
totalPower=sum(P); table(d(:,1),P,Cost,'V',{'Unit' 'Power' 'Cost'})
display(totalCost);
display(totalPower);
figure
plot(Iteration,totalCost_iteration)
title('Convergest Graph')
xlabel('Number of Iteration')
ylabel('Cost(RM/h)')
  2 comentarios
Muhammad Ezree Amree bin Amran
Muhammad Ezree Amree bin Amran el 4 de En. de 2021
Omg, thank you so much. I'm still wondering which part of it is wrong.
but thank you so much, Sir. Thank you.
Alan Stevens
Alan Stevens el 4 de En. de 2021
This was the line causing the probem
Lamda(i,1)=Lamda;

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