DOE points normal distrbution

Dear sir

if i have the mean and standarded deviation and I need to generate a number of points folowing the gaussien normal distrbution how can i do that please.

Answer 1

[David Hill]

m=standard_deviation.*randn(1,1000)+mean;%generates an array of 1000 numbers

[Hazim Hamad]

Many thanks ;

I have a question please .

if i have a mtrix of points and I need to generate new matrix include new points normally distrbuted based on each points consider as mean value for example point 1 x(1,1)= 0.1 and it is the mean and I need to generate 20 new points based on this point i created simple code but it is not working properly can you check it please.

x= [ 0.1 0.2 0.3 0.4

0.2 0.4 0.5 0.6 ] ;

% standard_deviation=0.1*x where x is avector of x1 , x2 ,x3 and x4 so the first row of x is x ( 0.1 0.2 0.3 0.4 )

% mean=x

% m=standard_deviation.*randn(1,1000)+mean

mean=x;

n=2

ndv=4

for i=1:n

for j =1:ndv

z(j,i)=mean(i,j);

z11=z'

end

end

for i=1:n

for j =1:ndv

mean1=z11;

% standard_deviation=0.1*mean(i,j);

% m=standard_deviation.*randn(1,5)+mean;

standard_deviation=0.1*mean1;

m=standard_deviation.*randn(20,4)+mean1;

end

end

[David Hill]

Not sure I understand you completely.

x= [.1,.2,.3,.4,.2,.4,.5,.6];%is there a reason why you can't make x just a row vector?
sd=.1*x;
n=sd.*randn(20,length(x))+x;%generates 20 numbers in each column corresponding to requested standard deviation and mean

[Hazim Hamad]

Many Thank this is because x is a matrix of design points and each row represents a case so your solution is correct for just one row would you help make it valid for two rows please.

x= [ 0.1 0.2 0.3 0.4

0.2 0.4 0.5 0.6 ] ;

ist row is 0.1 0.2 0.3 0.4

2nd row is 0.2 0.4 0.5 0.6

regards

Answer 2

[Hazim Hamad]

Hi

for the random normal distrbution can you help me to use seed to obtain the same result at each trail.

Regards

Hazzim