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Identify an array of arbitrary minimum values. Alternatives to min / find ?

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I would like to identify the occurences (index) of an arbitrary value within a Vector. The values I wish to identify will be close to but may not be exactly equal to this value.
For example having obtained the vector [Vector,t] = lsim(G,u,t) I would like to identify those points where the Vector assumedly intersects a horizontal line of given amplitude plot([X1 X2],[Y1 Y1])
I can obtain the first value quite simply with something along the lines of
[index value] = min(abs(abs(Vector) - abs(arbitrary_value)))
The find function is of some assitance however it requires that the arbitrary value equals the value of an element within the Vector exactly. Hence Idxs = find(A==MinValue) does not return a value within proximity of the intersection (or any point for that matter)
I thought I might be able to scrape by with a for loop i.e.
for i = 1:length(Vector)
if (Vector(i) - arbitrary_value) < tolerance
index(k) = i;
Value(k) = y(i);
k = k+1;
end
end
however it is far from an attractive or precise solution.
Any suggestions would be welcome.
Regards

Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 18 de Abr. de 2013
Editada: Andrei Bobrov el 18 de Abr. de 2013
eg:
tolerance = 1e-3;
ii = abs(Vector - arbitrary_value) < tolerance;
Value = Vector(ii);
index = find(ii);
ADD variant
t = vin - av;
idx = cellfun(@(x)strfind(sign(t(:).'),x),{0,[-1 1],[1 -1]},'un',0);
x0 = bsxfun(@plus,[idx{2:end}],(0:1)');
[~,ii] = min(abs(t(x0)));
iout = sort([[idx{1}],x0(sub2ind(size(x0),ii,1:size(x0,2)))]);
index = vin(iout);
  3 comentarios
Jamie
Jamie el 19 de Abr. de 2013
Superb. Many thanks for your assitance

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