Contour Plot of Rosie Function
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Hello,
I am trying to get the same plot as my professor showed in class. He said to use a for loop instead of meshgrid. I keep getting an error that X must not be a scalar. I'm not sure where I'm going wrong. Below is the plot I'm supposed to get followed by my code that is not working.
i=1; j=1;
x1=-1:.01:3;
x2=-1:.01:3;
for a=x1
for b=x2
f(i,j)=100*(a^2-b)^2+(1-a)^2;
j=j+1;
end
j=1;
i=i+1;
end
clf;figure(1)
contour(a,b,f)
3 comentarios
Adam Danz
el 24 de En. de 2021
I'm sure it's based on some dataset, function, or algorithm that our prof must have provided at some point.
Respuestas (1)
Star Strider
el 24 de En. de 2021
Transpose ‘f’, since ‘x1’ and ‘x2’ appear to be the same (otherwise it would also be necessary to reverse their orders in the argument list for the contour call):
i=1; j=1;
% conts=[-1 -.5 0 .5 2 3 3.5 3.6 3.7 3.8 3.9 3.98 4 4.02 4.1 4.2 4.5 5 10 ];
conts = 10.^(-1:1:3);
x1=-1:.01:3;
x2=-1:.01:3;
for a=x1
for b=x2
f(i,j)=100*(a^2-b)^2+(1-a)^2;
j=j+1;
end
j=1;
i=i+1;
end
% clf;
figure(1)
contour(x1,x2,f.',conts, 'ShowText','on', 'LineWidth',1.5)
axis('equal')
.
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