Can't use laplace transformed expression with transfer function.

2 visualizaciones (últimos 30 días)
When i laplace transform my expression ('r2') it becomes "sym" and i cant use it with any system or transfer function in the 's'-domain.
('r1') is numerically equivalent, but declared manually. it works fine.
Is there a way to make Laplace transforms become "tf"?

Respuesta aceptada

Rohit Pappu
Rohit Pappu el 29 de En. de 2021
A plausible solution is as follows
% Collect the coefficients of r2
h = collect(r2);
% Split the coefficients into numerator and denominator
[ii,jj] = numden(h);
% Convert the coefficients into numerical values
num = sym2poly(ii);
den = sym2poly(jj);
% Generate Transfer function from the above coefficients
model= tf(num,den);
  2 comentarios
Walter Roberson
Walter Roberson el 29 de En. de 2021
There can be additional work needed if there is a delay on the system. That shows up as an exp() term symbolically.
haavardmk
haavardmk el 29 de En. de 2021
Not simple, but it did work! thanks guys!

Iniciar sesión para comentar.

Más respuestas (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by