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Array in loop - Index exceeds the number of array elements (3) - problem

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Saud Alfalasi
Saud Alfalasi el 20 de Feb. de 2021
Comentada: Walter Roberson el 21 de Feb. de 2021
R = string(data{:});
conf_val = [R(1) "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "12" "13" "14" "15" "16" "17" "18" "19" "20" "21" "22" "23" "24" "25" "26" "27"];
for ii=1:27
if isempty(R(ii))
x = "nill";
else
x = R(ii);
end
text_str{ii} = ['Confidence: ' convertStringsToChars(x),'%s' '%'];
end
data = textscan(fileID,'%s');
fclose(fileID);
R = vertcat(data{:});
for ii=1:27
text_str{ii} = R{ii};
end
text string should have 27 elements.
I need a character vector of 27 strings read from a file.
if there are not 27 elements in my file, I would like to display 'nil' for that element at the missing index
Please can someone help
  6 comentarios
Saud Alfalasi
Saud Alfalasi el 20 de Feb. de 2021
@Mario Malic I understand the width of R is 3. However I would like it to be 27 - so if some lines of string from text are missing, It flags up yet my code still runs. The exact error message is in the title
Jan
Jan el 21 de Feb. de 2021
@Saud Alfalasi: "And please don't make asking questions an unpleseant experience - questions should be encouraged, this is how people learn."
I agree with you. When you mention this explicitly I'd like to add: Please keep it pleasent for others to answer questions. Imagine what would happen, if all users catch the attraction of the top ten answerers explicitly for all of their questions. This would be a reason for me to leave the forum to avoid stress.
I answer a question, if I find the time to read it and have an idea about a possible solution. A further pushing decreases your chance to get answers. Therefore Mario's hint is valuable and you can take it as a supoort.

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Respuestas (1)

Walter Roberson
Walter Roberson el 20 de Feb. de 2021
data = textscan(fileID,'%s');
fclose(fileID);
text_str = vertcat(data{:});
if length(text_str) > 27; text_str = text_str(1:27); end %in case it was too long
text_str(end+1:27) = {'nil'}; %if it was too short, put in nil
  5 comentarios
Saud Alfalasi
Saud Alfalasi el 21 de Feb. de 2021
Records = 'record.txt';
fileID2 = fopen(Records);
data = textscan(fileID2,'%s');
fclose(fileID2);
text_str = data{1:4};
mask = cellfun(@isempty, text_str);
text_str(mask) = {'nil'};
Hi guys, array element 4 doesn't exist,
The output I was expecting is
apple
pear
cheese
nil
However this is the output:
mask =
3×1 logical array
0
0
0
Walter Roberson
Walter Roberson el 21 de Feb. de 2021
You need to switch your method of reading entirely. I suggest that you use readlines() if you have a new enough matlab.

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