How to use reshape in specific case

Hi all, can anyone help me with reshaping 3D matrix to 2D in way shown below? Lets say I have a 3D matrix A (A = round(rand(3,3,3)*10))
A(:,:,1) =
0 8 7
1 9 4
1 3 5
A(:,:,2) =
7 5 5
10 7 7
8 4 0
A(:,:,3) =
2 7 4
5 8 8
2 4 6
And i want a 2D matrix C C =
0 8 7
1 9 4
1 3 5
7 5 5
10 7 7
8 4 0
2 7 4
5 8 8
2 4 6
Thank you for any input for this problem

 Respuesta aceptada

James Tursa
James Tursa el 13 de Mayo de 2013
Editada: James Tursa el 13 de Mayo de 2013
For your specific example,
reshape(permute(A,[1 3 2]),9,3)
Alter the last two dimensions to fit your actual problem. The purpose of the permute in the above expression is to get the 3rd dimension next to the 1st dimension in memory, and then a simple reshape will finish the job.

3 comentarios

Jan
Jan el 14 de Mayo de 2013
Thank you for your reply. Another liked question. How to do this in reverse? lets say I have a previosly created 2D matrix and I want to create 3D matrix. I am still not quite sure how to use permute.
Jan
Jan el 14 de Mayo de 2013
Never mind spend another 14 minutes to think of it twice. I appreciate yor help.
This worked
C = reshape(permute(B,[2 1]),3,3,3); NewC = permute(C, [2,1,3])
Andrei Bobrov
Andrei Bobrov el 14 de Mayo de 2013
Editada: Andrei Bobrov el 14 de Mayo de 2013
C = reshape(permute(A,[2 1 3]),3,[])'
A = permute(reshape(C,3,3,[]),[1 3 2])

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Jan
el 13 de Mayo de 2013

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