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How can I extract a slice from a multidimensional array?

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I have an array of variable dimensions and want to extract a slice of it.
If I the size of the array was fixed I would like to do:
result = G(:,:,:,r,:,:);
But in my case, r is a variable and so are the dimensions of G and the dimension from which I want to extract the slice (in this case the 4th dimension).
-----------------------------------
I am able to costruct a cell array containing the indices that need to be extracted, but can't extract them.
N = ndims(G);
other_dimensions = [1:(n-1),(n+1):N];
sz = size(G);
inds = repmat({r},1,ndims(G));
for k = 1:length(other_dimensions)
inds{other_dimensions(k)} = 1:sz(other_dimensions(k));
end
result = A(inds) % (not working)

Accepted Answer

Stephen Cobeldick
Stephen Cobeldick on 27 Feb 2021
Edited: Stephen Cobeldick on 27 Feb 2021
The trick here is to define a cell array and then use a comma-separated list for the indices. For example:
G = rand(7,6,5,4,3,2); % any size
d = 4; % which dimension
r = 3; % index in that dim.
% define cell array:
C = repmat({':'},1,ndims(G));
C{d} = r;
% comma-separated list to supply indices:
S = G(C{:}); % get slice!
% check:
size(G) % original array
ans = 1×6
7 6 5 4 3 2
size(S) % slice
ans = 1×6
7 6 5 1 3 2
isequal(S,G(:,:,:,r,:,:))
ans = logical
1
  1 Comment
Uri Goldsztejn
Uri Goldsztejn on 1 Mar 2021
Thank you for your answer! I realized I could change 1:sz(other_dimensions(k)) for ':' in my code and solve the problem as well. I.e.,
N = ndims(G);
other_dimensions = [1:(n-1),(n+1):N];
sz = size(G);
inds = repmat({r},1,ndims(G));
for k = 1:length(other_dimensions)
inds{other_dimensions(k)} = ':';
end
result = A(inds) % (now it works)

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