Linear programming code not showing the solution
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I extracted the following code from an online pdf that solves basic feasible solution of linear programming problems.
function vert = feassol(A, b)
% Basic feasible solutions vert to the system of constraints
% Ax = b, x >= 0.
% They are stored in columns of the matrix vert.
[m, n] = size(A);
warning off
b = b(:);
vert = [];
if (n >= m)
t = nchoosek(1:n,m);
nv = nchoosek(n,m);
for i = 1:nv
y = zeros(n,1);
x = A(:,t(i,:))\b;
if all(x >= 0 & (x ~= inf & x ~= -inf))
y(t (i, :)) = x;
end
end
else
error('Nuber of equations is greater than th neumber of variables.')
end
if ~isempty(vert)
vert = delcols(vert);
else
vert = [];
end
end
To test the code, the author used the system
A = [1 1 1 0; 0 1 0 1];
b = [6; 3];
and obtain the results
vert = feassol(A, b)
vert =
0 0 3 6
0 3 3 0
6 3 0 0
3 0 0 3
But whenever I run the code, I get
>> vert = feassol(A,b)
vert =
[]
What am I not doing right with the code? Any help will be much appreciated. Thanks in advance!
Respuestas (2)
Walter Roberson
el 27 de Feb. de 2021
0 votos
Where do you assign something nonempty to vert?
Why do you calculate y since you never use it?
9 comentarios
Walter Roberson
el 27 de Feb. de 2021
vert(:, end+1) = y;
Hmm!
el 27 de Feb. de 2021
Walter Roberson
el 27 de Feb. de 2021
function vert = feassol(A, b)
% Basic feasible solutions vert to the system of constraints
% Ax = b, x >= 0.
% They are stored in columns of the matrix vert.
[m, n] = size(A);
warning off
b = b(:);
vert = [];
if (n >= m)
t = nchoosek(1:n,m);
nv = nchoosek(n,m);
for i = 1:nv
y = zeros(n,1);
x = A(:,t(i,:))\b;
if all(x >= 0 & (x ~= inf & x ~= -inf))
y(t (i, :)) = x;
vert(:, end+1) = y;
end
end
else
error('Nuber of equations is greater than th neumber of variables.')
end
if ~isempty(vert)
vert = delcols(vert);
else
vert = [];
end
end
Walter Roberson
el 27 de Feb. de 2021
note that you test x>=0 but you also test about negative infinity. A nonnegative value cannot be negative infinity.
Walter Roberson
el 27 de Feb. de 2021
Also if you got that error message then you passed in an array with more rows than columns.
Hmm!
el 27 de Feb. de 2021
Walter Roberson
el 27 de Feb. de 2021
I do not know. You called decols in the code you supplied; no documentation has been supplied as to its purpose or its implementation.
But if I were to guess... I would guess it probably isn't needed.
Hmm!
el 28 de Feb. de 2021
As long as your feasible set is bounded, you can use this FEX submission instead,
A = [1 1 1 0; 0 1 0 1];
b = [6; 3];
[args{1:4}]=addBounds([],[],A,b,[0;0;0;0]);
vert=lcon2vert(args{:}).'
for which I get the result,
vert =
6.0000 3.0000 -0.0000 -0.0000
0.0000 3.0000 3.0000 -0.0000
-0.0000 0 3.0000 6.0000
3.0000 0 0 3.0000
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