How to work on "for loop" to save different column variable values to single vector?

My question is=>

i have two variables, Ea and Ed, Ea contains single value and Ed contains 4 values like this,

Ea=10.5

Ed=51.6149 27.1981 13.2580 2.3396

These are wave energy values for 1 second of audio clip. But i have to calculate energy values for 60 seconds. So i have done storing each energy values in different variables like, Ed1, Ed2, Ed3...Ed60. These are Ed values for 60 seconds.

Now the problem i ve got is=>

i want to store all 1st column values of each variable(Ed1,Ed2,Ed3 till Ed60) in one vector(VEd1,VEd2,VEd3 and VEd4), so that i can draw or plot graph to analyze.

Here VEd1 should contain only 1st column values of all Ed values and also VEd2, VEd3 and VEd4.

I have tried "for" loop but could not get how to do tat... If i wont use any loops here, i wont b able to finish this before my dead line as i have to train the module for different audios.

Here is whatever i have tried... but i got errors...

 for i=1:60,
    VEa=Ea(i);
 end
 ERROR: Attempted to access Ea(2); index out of bounds because numel(Ea)=1.

then tried=>

 for i=1:60,
    VEa=Ea.i;
 end
 ERROR: Attempt to reference field of non-structure array.

Then i satisfied with this=>

 for i=1,
    VEd1=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
 end

 for i=2,
   VEd2=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
  end

for i=3,
   VEd3=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end

for i=4,
   VEd4=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end

NOW can u plz tel me how to do all this in a single loop?

i want to know how this all variables can be used to store the appropriate values... As in C- language its not happening here. if u know something about this plz help me... Thank you...

Answer 1

[SL B]

Why loop when you can just put it in a matrix? You are saying that Ed1 = [51.6149 27.1981 13.2580 2.3396] (this would be a row, but I'm assuming you have it in columns since you said you want the first value in each column of EdXX)

so assuming Edxx are column vectors:

Ed = [Ed1, Ed2, Ed3,.......,Ed60];

Then

Ved1 = Ed(1,:);
Ved2 = Ed(2,:);
Ved3 = Ed(3,:);
Ved4 = Ed(4,:);

[prasanna patil]

Now u will understand what i meant clearly.

 x= input('loop starts from-> ', 's'); 
 y= input('loop starts from-> ', 's'); 
 for i=x:y, 
 Tw = 25; 
 Ts = 10;
 alpha = 0.97;
 R = [ 300 3700 ];
 M = 20;
 C = 13;
 L = 22;
 hamming = @(N)(0.54-0.46*cos(2*pi*[0:N-1].'/(N-1)));
 x= input('input the audio file-> ', 's'); 
 [ speech, fs, nbits ] = wavread(x);
 [MFCCs,FBEs,frames]= mfcc(speech,fs,Tw,Ts,alpha,hamming, R, M, C, L );
 [C,L] = wavedec(MFCCs,4,'sym4');
 [Ea,Ed] = wenergy(C,L);
 VEa(i)=Ea(1);
 VEd1(i)=Ed(1);
 VEd2(i)=Ed(2);
 VEd3(i)=Ed(3);
 VEd4(i)=Ed(4);
 end

the output will b like this...

 loop starts from-> 1
 loop starts from-> 2
 input the audio file-> 1.wav
 input the audio file-> 2.wav

now i can store energy values for many audios in different variables with a single program. :)

Answer 2

[David Sanchez]

for i=1:4
VEd(k) = [Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end

[prasanna patil]

sir, i am not clear with your answer. How can i store separate 60 values in 4 separate variables?

I tried on your code but i didn't get what i wanted.

As u said that ll process like this...

 for i=1:4,
   v(i)=i;
 end
>> v

v =

     1     2     3     4

[prasanna patil]

and tried this also...

 for k=1:4,i=1:4,
     VEd(k) = [Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end

i =

     1     2     3     4

ERROR: In an assignment A(I) = B, the number of elements in B and I must be the same.